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dalvyx [7]
3 years ago
15

Write a quadratic function that has a minimum value and how do you know it has a minimum value?

Mathematics
1 answer:
sweet [91]3 years ago
7 0

Put the quadratic in standard form f(x) = a(x − h)2 + k, and the absolute maximum/minimum value is k and it occurs at x = h. If a > 0, then the parabola opens up, and it is a minimum functional value of f. If a < 0, then the parabola opens down, and it is a minimum functional value of f.
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Please help me with segment addition and midpoints
Tanya [424]

Answer:

3

Step-by-step explanation:

Since we know QR and RS are the same, we can add them together

6 + 6 = 12

Since the whole line is 15 we subtract 12 from 15

15 - 12 = 3

8 0
2 years ago
Simplify. e^(in x)=, e^(in 5)=, e^(in 3x)=
Pepsi [2]

Answer:

Step-by-step explanation:

e^ lnx  = x

e^ ln5 = 5

e^ ln 3x = 3x

I think you get the idea... e is an inverse operation to ln  :o

5 0
3 years ago
How do I do numbers 1, 2 and 3
stiks02 [169]
What you want to do for each of those is follow the formula, y-y[1]=m(x-x[1]). When I say y[1] and x[1], I mean the x and y values given. So the first one would be y-4=-3(x-(-1)). Then you solve for y by distributing the -3 to x and +1 (+1 because two negatives make a positive), making the equation
y-4=-3x-3. Then you subtract the 4. Answer #1. y=-3x-7. 

#2. 
y-1=1(x-4)
y-1=x-4
y=x-5

#3.
y-2=2(x-(-1))
y-2=2x+2
y=2x+4

Hope this helped you!

8 0
3 years ago
What is the answer to |x-4|&lt;13
VARVARA [1.3K]

Answer:

<h2>The solution is -9 < x < 17.</h2>

Step-by-step explanation:

|x-4|<13.

The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.

Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.

7 0
3 years ago
Write the following as ratio and simplif 3km to 12km <br>​
lesantik [10]

Answer:

1:4

Step-by-step explanation:

3:12

((3×1):(3×4))

=1:4

(would love if you could mark me the brainliest :))

3 0
2 years ago
Read 2 more answers
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