What is not a climate Factor?

The bond between carbon and hydrogen is one of the most important types of bonds in chemistry. The length of an H—C bond is appr

nata0808 [166]

Answer:

The dipole moment of H-C bond will be smaller than that of an H-I bond.

Explanation:

The electronegativity of iodine is greater than that of hydrogen.As a result the iodine atom tends to attract the bond electron pair of H-I bond towards itself creating a bond dipole which does not occur in case of H-C bond as the electronegativity of carbon and hydrogen are almost same.

That"s why dipole moment of H-C bond is smaller than that of H-I bond.

7 0

3 years ago

If the earth was a guava fruit, the space where the seeds are would be the core/mantle

Bezzdna [24]

Good analysis lol ...

8 0

3 years ago

Read 2 more answers

What is a good business atmosphere ?

Ivanshal [37]

A good business atmosphere is an environment where everything is calm, maintaining, and positive. There also has to be good communication because, communication is key to a stress free atmosphere. everyone should work well and efficiently together. That is a good business atmosphere.

Hope this helps :)

6 0

3 years ago

12. How many moles of atoms are present in 154 g of Na2O?

tia_tia [17]

Answer:

$\boxed {\boxed {\sf A. \ 2.48 \ mol \ Na_2O}}$

Explanation:

We are asked to convert an amount in grams to moles. To do this, we use the molar mass. This is the number of grams in one mole of a substance. It is the same value numerically as the atomic mass on the Periodic Table, however the units are grams per mole, not atomic mass units.

Look up the molar masses for the individual elements.

Sodium (Na): 22.9897693 g/mol
Oxygen (O): 15.999 g/mol

Look back at the formula: Na₂O. Notice there is a subscript of 2 after sodium. This means there are 2 atoms of sodium in every molecule, so we have to multiply sodium's molar mass by 2 before adding oxygen's.

Na₂O: 2(22.9897693 g/mol)+ 15.999 g/mol = 61.9785386 g/mol

Set up a ratio using the molar mass.

$\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}$

Multiply by the given number of grams.

$154 \ g \ Na_2O*\frac {61.9785386 \ g \ Na_2O}{1 \ mol \ Na_2O}$

Flip the ratio so the grams of sodium oxide can cancel each other out.

$154 \ g \ Na_2O*\frac {1 \ mol \ Na_2O}{61.9785386 \ g \ Na_2O}$

$154 *\frac {1 \ mol \ Na_2O}{61.9785386 }$

$\frac {154}{61.9785386 } \ mol \ Na_2O$

$2.48473106141 \ mol \ Na_2O$

The original measurement of grams given has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

2.48<u>4</u>73106141

The 4 in the thousandth place tells us to leave the 8.

$2.48 \ mol \ Na_2O$

There are <u>2.48 moles of sodium oxide</u> in 154 grams, so choice A is correct.

6 0

3 years ago

What contains more than one pair of electrons?

Elis [28]

Answer: A Covalent Bond

Explanation:

5 0

3 years ago