3 by 10kg? ioooooooooooooo
C r = (n!)/(r!(n-r)!)
9 C 3 = (9!)/(3!*(9-3)!)
9 C 3 = (9!)/(3!*6!)
9 C 3 = (9*8*7*6!)/(3!*6!)
9 C 3 = (9*8*7)/(3!)
9 C 3 = (9*8*7)/(3*2*1)
9 C 3 = (504)/(6) 9 C 3 = 84
Hey there!
Solve using pythagoras theorem (it's given that is triangle is right angled. Pythagoras theorem only works in the case of right triangles) ⇨ Hypotenuse² = Base² + Altitude ²
Here,
Base = 9 mm
Hypotenuse = 15 mm
Altitude = b
Hypotenuse² = Base² + Altitude ²
15² = 9² + b²
225 = 81 + b²
225 - 81 = b²
144 = b²
√144 = b
<u>1</u><u>2</u><u> </u><u>mm </u>= b
Hope it helps ya!
https://www.wolframalpha.com/
Answer: 
Step-by-step explanation:
You need to use the following formula that is used to find the area of a trapezoid:

Where "M"and "m" are the bases of the trapezoid and "h" is the height of the trapezoid.
Based on the information given in the exercise, you can identify that:

Knowing these values, you can substitute them into the formula:

Finally, you must evaluate in order to find its area. This is:
