<span><span>x3</span>+3<span>x2</span>−9x−27=<span>(x−3)</span><span>(x+3)</span><span>(x+3<span>)</span></span></span>
Answer:
Step-by-step explanation:
Given two upward facing parabolas with equations

The two intersect at


=
x=
area enclosed by them is given by
A=![\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx](https://tex.z-dn.net/?f=%5Cint_%7B-%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5E%7B%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5Cleft%20%5B%20%5Cleft%20%28%20x%5E2%2B2%5Cright%20%29-%5Cleft%20%28%206x%5E2%5Cright%20%29%20%5Cright%20%5Ddx)
A=
A=
A=
It would be 330 if rounded to the nearest 10th place
The slope of the line has to be the same the the equation given to be parallel.
The slope of the line given is... 2/3.
If the line passes through point (1,3) then...
3=2/3(1)+b
b=2 1/3
answer: y=2/3x+2 1/3