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Orlov [11]
3 years ago
13

Which of the following is true of the values of x and y in the diagram below?

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer: y/x = 1

Step-by-step explanation:

It was on quizlet

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If f(x) = - x + 4 and g(x) = x ^ 2 - 5 , then f(g(-2))=?
kkurt [141]

Answer:

Step-by-step explanation:

using your f(x) I want to show you how to plug in different things itnot he function.

f(x) = -x + 4

f(1) = -1 + 4 = 3

f(2) = -2 + 4 = 2

f(m) = -m + 4

f(abc) = -(abc) + 4

f(h(x)) = -h(x) + 4

Does that help?  what if you replaced h(x) with g(x)?  Of course you already have that x so you could make it a little simpler as well.  Let me know if you don't quite get it.

5 0
4 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
The size your dog and the number of times you take it to the vet, The amount your drive to school and the amount you have to pay
rosijanka [135]

1. No correlation

Those things don't really relate to each other.

2. Positive correlation

The more you drive your car, the more you'll have to pay for gas.

3. Negative correlation

More people = less soda.

7 0
3 years ago
The end of a hose was resting on the ground, pointing up an angle. Sal measured the path of the water coming out of the hose and
lawyer [7]

Functions can be used to model real life situations.

The hose is 3.2 feet above the ground, at a horizontal distance of 4 fee

The function is given as:

f(x) =-0.3x^2 + 2x

At a horizontal distance of 4 feet, the value of x is 4

i.e. x = 4

Substitute 4 for x in f(x).

So, we have:

f(4) =-0.3(4)^2 + 2(4)

Evaluate the exponent

f(4) =-0.3(16) + 2(4)

Open both brackets

f(4) =-4.8 + 8

Add -4.8 and 8

f(4) =3.2

Hence, the hose is 3.2 feet above the ground

Read more about functions at:

brainly.com/question/10837575

7 0
3 years ago
Bianca wrote the steps for her solution to the equation 2.3 + 8(1.3x – 4.75) = 629.9. She left out the description for the last
Virty [35]

I believe dividing is always the last step.


5 0
3 years ago
Read 2 more answers
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