Which of the following is true of the values of x and y in the diagram below?

Using traditional methods, it takes 94 hours to receive a basic flying license. A new license training method using Computer Aid

nikdorinn [45]

Answer:

$z=\frac{95-94}{\frac{5}{\sqrt{210}}}=2.898$

$p_v =2*P(Z>2.898)=0.0038$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 94 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=95$ represent the sample mean

$\sigma=5$ represent the population standard deviation

$n=210$ sample size

$\mu_o =94$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different from 94, the system of hypothesis are :

Null hypothesis: $\mu = 94$

Alternative hypothesis: $\mu \neq 94$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{95-94}{\frac{5}{\sqrt{210}}}=2.898$

P-value

Since is a two-sided test the p value would be:

$p_v =2*P(Z>2.898)=0.0038$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 94 at 5% of signficance.

8 0

3 years ago

(w15/w5)^4 Simplify it.

Stells [14]

$Solution, \left(\frac{w^{15}}{w^5}\right)^4=w^{40}$