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2 years ago

If you roll a number cube 20 times, about how many times do you expect

Mathematics

1 answer:

patriot [66]2 years ago

8 0

Answer:

is this a math question or something?

Step-by-step explanation:

You might be interested in

The value of b when solving the equation 2 (6 + 12) = 16 is:

elena-s [515]

Answer:

Step-by-step explanation:

2(6+12)=16

2 X 6 + 2 X 12

12 + 24

26 = 16

HOPE U GE5T IT

8 0

2 years ago

Describe the surface in 3 represented by the equation x + y = 5. This is the set {(x, 5 − x, z)|x , z } which is a vertical plan

KengaRu [80]

treonvty trwqnty ewuit

7 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

2 years ago

HELP^^ LOOK AT THE PICTURE. this is algebra in & out tables ?

s2008m [1.1K]

Answer:

a= 1 , b = 1/16 , c = 1/256 , d= 3/2 , e=4/9 , f= 16/81

Step-by-step explanation:

The first table is given as;

x 4⁻ˣ

-1 4

0 1

2 1/16

4 1/256

a= 1 , b = 1/16 , c = 1/256

The second table is given as;

x {2/3}^x

-1 3/2

0 1

2 4/9

4 16/81

d= 3/2 , e=4/9 , f= 16/81

5 0

3 years ago

H(1) = -26 h(n) = h(n-1) x (-9) Find an explicit formula for h(n). h(n)= ___

ValentinkaMS [17]

Answer:

you do not have to state explicitly which limit law(s) you are using. 1 - 5n ... Q: 9) n(x) = 2x - 2 g(x)= x2 + 5 Find h(g(1) A) 5 B) 10 C) 21 D) 40.

Step-by-step explanation:

4 0

3 years ago