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3 years ago

NEED HELP DUE IN 10 MINUTES!!!

Mathematics

1 answer:

slavikrds [6]3 years ago

3 0

Where is the question? I would be more than happy to help you but you did not post a question

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Factor each trinomial completely.<br> 4x^2 - 25b^2 and x^2 - 81

GenaCL600 [577]

Step-by-step explanation:

4x2 - 25b2

We can solve it by the squares so

(2x - 5b) (2x + 5b)

2) x2 - 81

The same case is here so

(x - 9) (x + 9)

8 0

3 years ago

Please help, I don’t really understand this

shtirl [24]

A earns $350×0.04×5 = $70 interest in interest over five years.

B earns $500×0.035×5 = $87.50 in interest over five years.

Do C the same way.

5 0

3 years ago

Please help, I’ll mark your answer as brainliest.

Brrunno [24]

Answers:

$(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\$

========================================================

Work shown for part 1

$f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\$

----------------------------------

Work shown for part 2

$(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\$

6 0

2 years ago

The number of ferryboat trips r(c) needed to transport c cars in 1 day can be found using the function f(c)=c/20. If there are n

xz_007 [3.2K]

<h2>Hello!</h2>

The answer is:

The range of the given function, f(c) is

$f(c)\leq 250$

To solve the problem we need to remember that a function is a relationship between an input usually called "x" (domain) and an output, usually called "y" and it's also the range of the function.

$f(x)=y$

We are given a relationship (a function) between the ferryboat trips "c" and the number of cars transported per day.

$f(c)=\frac{c}{20}$

Also, we know that there are not more than 5000 cars transported by the ferryboat, so, let's make this value our input, in order to find the output (range) of the given function.

So, if

$c=5000$

Evaluating, we have:

$f(5000)=\frac{5000}{20}=250$

Hence, the range of the function knowing that there are not more than 5000 cars transported by the ferryboat (daily) the range is all the numbers that are less or equal to 250.

$f(c)\leq 250$

Have a nice day!

8 0

3 years ago

Sunny went bowling with her friends. She paid $4.50 to rent shoes, and then $6.25 for each game of bowling. If she spent $42, th

fomenos

Pretty sure its my guy

5 0

3 years ago