Answer:
I think system 4 has no solution
Step-by-step explanation:
I'm sorry if you get it wrong
The mass of the first shipment at time t is

The mass of the second shipment at time t is

At time t, the ratio of m₁ to m₂ is

Therefore as a percentage,

Answer: B. 81.2%
Answer:
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Step-by-step explanation:
The larger one is (-11 + 41)/2 = 15.
The smaller one is (-11 -41)/2 = -26.
_____
For two numbers a and b with sum s and difference d, you can write the equations

Then adding the equations and dividing that sum by 2, you get

You can subtract the second eqution from the first and get a similar result for the smaller number

These are the formulas we used above.