Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.
Answer: 7.7759 x 10⁻¹ times
Answer:
Step-by-step explanation:
A=LxW
Answer:
an = 2·2^(n-1)
Step-by-step explanation:
There are simple tests to determine whether a sequence is arithmetic or geometric. The test for an arithmetic sequence is to check to see if the differences between terms are the same. Here the differences are 2, 4, 8, so are not the same.
The test for a geometric sequence is to check to see if the ratios of terms are the same. Here, the ratios are ...
4/2 = 2
8/4 = 2
16/8 = 2
These ratios are all the same (they are "common"), so the sequence is geometric.
The general term of a geometric sequence with first term a1 and common ratio r is ...
an = a1·r^(n-1)
Filling in the values for this sequence, we find the general term to be ...
an = 2·2^(n-1)
