Answer:
![\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
Step-by-step explanation:
We can simplify the expression under the root first.
Remember to use 
Thus, we have:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D%20%5C%5C%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
We know 4th root can be written as "to the power 1/4th". Then we can use the property 
<em>So we have:</em>
<em>![\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D%20%5C%5C%3D%28%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D%5Cfrac%7B3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2y%7D%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
</em>
<em />
<em>Option D is right.</em>
Answer:
The final position is 5 feet below the back of the truck
Step-by-step explanation:
* Lets explain how to solve the problem
- A crane lifts a pallet of concrete blocks 8 feet from the back of
a truck
- The crane lowers the pallet 13 feet after the truck drives away
- Assume that the zero level of the position of the ballet of concrete
blocks is the back of the truck
∵ The crane lifts the pallet of concrete blocks 8 feet from the back
of the truck
- That means it take the pallet from zero to 8
∴ The height of the pallet of concrete blocks is 8 feet over
the starting position
∵ The crane lowers the pallet of concrete blocks 13 feet
- That means the crane lower the pallet from the height 8 and
lift it down 13 feet, so we must to take out from the 8 feet the
13 feet to find the final position of the pallet of concrete blocks
∴ The pallet position is ⇒ 8 - 13 = -5
∴ The position of the pallet of concrete blocks is 5 feet below the
starting position which is the back of the truck
* The final position is 5 feet below the back of the truck
I think it might be D
The size of the sample space is the total number of possible outcomes. For example, when you roll 1 die, the sample space is 1, 2, 3, 4, 5, or 6. So the size of the sample space is 6. Then you need to determine the size of the event space.
Answer:
DM
Step-by-step explanation:
We can represent the pizza as 1. And every time we take a slice, we take percentage away. This pizza is cut up equally into 10 slices. So, if we take away a slice, we take away 1/10 of the pizza. What if Sally ate 6 slices? Same difference. She took away 6/10 of the pizza.
And to answer the question, "What percentage of the pizza did Sally eat if she had six slices?"
We will convert the 6/10 into a percentage. First convert the fraction into a decimal then into a percent.
To convert a fraction into a decimal, simply divide it's numerator by it's denominator.
6/10 = 0.60
And to convert a decimal into a percentage, move the decimal point two places to the right and change it into a % sign.
0.60 = 60%
So, the answer to this question C) 60%
If you are still confused, DM me and I'll do my best to help!
Answer:
The proportion of bricks that crack during the firing process is 0.0001 = 0.01%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean of 925 and a standard deviation of 60 degrees.
This means that 
The proportion of bricks that crack during the firing process is closest to
This is 1 subtracted by the pvalue of Z when X = 1150. So
has a pvalue of 0.9999
1 - 0.9999 = 0.0001
The proportion of bricks that crack during the firing process is 0.0001 = 0.01%.
