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Ierofanga [76]
3 years ago
15

How do you reflect an image across the y axis

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0
The y-axis<span> is the point (-x,</span>y<span>). </span>Reflect over the y<span> = x: When you </span>reflect<span> a point </span>across<span> the line </span>y<span> = x, the x-coordinate and </span>y<span>-coordinate change places. If you </span>reflect over<span> the line </span>y<span> = -x, the x-coordinate and </span>y<span>-coordinate change places and are negated (the signs are changed)</span>
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Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?
bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for x=-6 in the function and simplify the function.

Hence, let us substitute x=-6 in the function, we get,

f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}

Let us apply the rule -\left(-a\right)=a , we get,

f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}

Multiplying the numbers, we get,

f(-6)=\frac{100}{-10+e^{0.6}}

The value of e^{0.6}=1.822

Substituting the value of e^{0.6}=1.822 , we get,

f(-6)=\frac{100}{-10+1.822}

Subtracting the denominator, we have,

f(-6)=\frac{100}{-8.178}

Dividing, we have,

f(-6)=-12.228

Rounding off to the nearest tenth, we have,

f(-6)=-12.2

Thus, the value of f(-6) is -12.2

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