C= two step equations require all number to be whole number in order to solve.

Here is an example that disproves that:
.5x + 8= 18
 -8 -8
.5x = 10
.5 .5

x = 20 (.5 is certainly not a whole number but I solved it anyway)

6 0

3 years ago

Read 2 more answers

I just need 30 please

PIT_PIT [208]

In the smaller triangle, let $y$ be the length of the smallest leg. Then the smallest leg in the larger triangle is $14-y$ .

Within the scope of the smaller triangle, we have $y$ such that

$x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}$

Then within the larger the triangle, we would have

$x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2$

Now we can solve for $x$ :

$x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2$

$\implies x=12$

8 0

3 years ago

Find the difference between points M(6,16) and Z(-1,14) to the nearest tenth.

svlad2 [7]

I'm not sure what you mean by difference, so I am guessing you meant to write "distance". If this is not the case, then feel free to report me. Anyway, to find the distance between two points you would use the distance formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Let's substitute our point coordinates into the formula. We'll substitute -1 and 6 for x_2 and x_1, and 14 and 16 for y_2 and y_1. After substituting, your formula will now look like: $d=\sqrt{(-1-6)^2+(14-16)^2}$ .