5x49=245 this is simple math
y=x²-10x-7
a>0 so we will be looking for minimum
x=-b/2a=10/2=5
y=25-50-7=-32
Answer: (5;32)
y=-4x²-8x+1
а<0 so we will be looking for maximum
х=-b/2a=8/-8=-1
у=4+8+1=13
Maximum point (-1;13)
(180(total angle measure of triangle)-50(EFG))/2(the other two angles have the same measure)=65
The angle CGE=180=CGF+EGF
180-65=CGF
115=CGF
<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
56 minutes for 5 people to paint 10 walls multiply by 5 to get 1 persondivide by 7 to get 7 peopledivide by 10 to get 1 wall multiply by 8 to get 8 walls(56)5*8)/(10*7) minutes for 7 people to paint 8 walls2240/70 = 32 minutes
