Trapezoid
x = 13.5 m - 7.5m / 2
= 6/2
= 3 m
Therefore x = 3 m
y = a^2=b^2 + c^2
= a^2 = 9^2 + 3^2
= a^2 = 90
= a = 9.5m
Therefore y = 9.5m
Perimeter = a+b+c+d
= 9.5 + 9.5 + 7.5 + 13.5
= 40m
Area= a+b/2 h
= 7.5+13.5/2 x 9
= 94.5 m^2
Kite
Area= p x q /2
= 12 x 9 /2
= 54 m^2
Answer:
380 different ways
Step-by-step explanation:
We can solve this problem using a permutation formula, as the order in a group of two students matter.
So, for this problem, we have 20 students and want to form groups of 2, so we have a permutation of 20 choose 2:
P(20,2) = 20! / (20-2)! = 20! / 18! = 20 * 19 = 380 different ways
Another way to solve this problem is:
For the first student being chose, we have 20 students available, and for the second student, we have just 19, as one was already chose, so the number of ways to choose these two students is 20 * 19 = 380
Answer:
<em>Addison worked 5 hours</em>
Step-by-step explanation:
<u>Proportions
</u>
A direct proportion is a relation between variables where their ratio is a constant value. This means that if y and x are proportional, then:
y = kx
Where k is the constant of proportionality.
The relationship between the number of kilograms of dough Addison prepares (y) is proportional to the number of hours he works on it (x).
Knowing he prepared y=30 kilograms of dough after t=3 hours, we substitute in the function:
30 = 3k
Solving for k:
k = 30/3 = 10
The relationship is:
y = 10x
If he prepared y=50 kg of dough, then:
50 = 10x
Solving for x
x = 50/10 = 5
Addison worked 5 hours
The line parallel to 5y - 4x=10, that passes through (-15, 8) is
y=4/5x +20
<h2>
The required "option D) 54 + 42 = 6(9 + 7)" is correct.</h2>
Step-by-step explanation:
We have,
The sum of 42 and 54
= 42 + 54
∴ 42 and 54
42 = 2 × 3 × 7 and
54 = 2 × 3 × 3 × 3
The greatest common factor of 42 and 54
= 2 × 3
= 6
∴ 42 + 54
= 6(7 + 9)
= 6(9 + 7)
Thus, the required "option D) 54 + 42 = 6(9 + 7)" is correct.