22. What is the value of x2 - 2xy + 2y2 when x = 2, y = 3?<br> A. 8<br> B. 10<br> C. 12<br> D. 14

this month salespersons a made 11% of $67,530. salesperson b made 8% of $85,740. who made more commission this month? how much d

Paul [167]

Salesperson A made $7428.30
Salesperson B made $6859.20
Salesperson A made more commission this month and made $7428.30

7 0

3 years ago

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∆PQR has vertices P(5, –2), Q(1, –4), and R(3,3).Reflect ∆PQR about the y-axis, translate 4 units down, and reflect about the x-

JulsSmile [24]

Answer:

P(-5,6) Q(-1,8) R(-3,1)

3 0

3 years ago

Simplify 2(a+5)−3(5a−4)

Nutka1998 [239]

Answer:

$-13a+22$

Step-by-step explanation:

we have

$2(a+5)-3(5a-4)$

step 1

Apply the distributive property both terms

$2a+2(5)-3(5a)+3(4)$

$2a+10-15a+12$

step 2

Combine like terms

$(2a-15a)+(10+12)$

$(-13a)+(22)$

$-13a+22$

4 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Need help with this question!

rosijanka [135]

Not sure:((((((( sorrryyyy

3 0

3 years ago

Read 2 more answers

22. What is the value of x2 - 2xy + 2y2 when x = 2, y = 3? A. 8 B. 10 C. 12 D. 14