I need help on this question plz

Mathematics

2 answers:

yuradex [85]3 years ago

8 0

If v = 6
6=m=3

6=3+3
3+3=6
hope i explained it good

Kitty [74]3 years ago

6 0

The correct answer will be 3.

Why?

If v = m + 3 what is m?

Well it's says that D = m/v and D = 3/6.

So if M is 3, what number can you add my 3 that is gonna equal to V (6).

3 + 3 = 6 and that's how I got my answer.

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Help me answer please

fiasKO [112]

Answer:

Step-by-step explanation:

b=4x+1 h=x+1 A=175

A=bh

Substitute: 175=(4x+1)(x+1)

Expand: 175=4x^2+5x+1

Subtract 175

4x^2+5x-174=0

Solve w/quadratic formula

(-5 + sqrt(25+2784))/8

Simplify: x=6 or -29/4

Distance is positive, so x=6

4x+1=4*6+1=25

6 0

2 years ago

What is the remainder of (4x2 + 7x-1)= (4 + x)? A. -9x – 1 B.23x – 1 C.35 D.-37

bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

$x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\$

Step-by-step explanation:

$\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}$

$\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\$

$\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}$