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Jobisdone [24]
3 years ago
14

PLEASE ANSWER ANY PROBLEM ASAP THANK YOU SO MUCH

Mathematics
2 answers:
Whitepunk [10]3 years ago
6 0
10: x=8



Sorry that’s all I know
Aloiza [94]3 years ago
5 0

Answer:

7) x = 2

8) x = 3

9) x = -7

10) x = 8

Step-by-step explanation:

7)

9x + 12 = 5x + 20

4x = 8

x = 2

8)

2x + 12 = 6x

4x = 12

x = 3

9)

62 + x + 125 = 180

x = -7

10)

arc WX = 2(35) = 70 degrees

12x + 14 + 70 = 180 degrees

12x = 96 degrees

x = 8

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tester [92]
The answer i D because 11-6=5
8 0
2 years ago
Which values for h and k are used to write the function f of x = x squared 12 x 6 in vertex form?
Nesterboy [21]

The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30

<h3>How to rewrite in vertex form?</h3>

The equation is given as:

f(x) = x^2 + 12x + 6

Rewrite as:

x^2 + 12x + 6 = 0

Subtract 6 from both sides

x^2 + 12x = -6

Take the coefficient of x

k = 12

Divide by 2

k/2 = 6

Square both sides

(k/2)^2 = 36

Add 36 to both sides of x^2 + 12x = -6

x^2 + 12x + 36= -6 + 36

Evaluate the sum

x^2 + 12x + 36= 30

Express as perfect square

(x + 6)^2 = 30

Subtract 30 from both sides

(x + 6)^2 -30 = 0

So, the equation f(x) = x^2 + 12x + 6 becomes

f(x) = (x + 6)^2 -30

A quadratic equation in vertex form is represented as:

f(x) = a(x - h)^2 + k

Where:

Vertex = (h,k)

By comparison, we have:

(h,k) = (-6,-30)

Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

3 0
2 years ago
Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).​
Len [333]

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

|AB|=\sqrt{1^2+2^2}=\sqrt{5};

|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};

|AD|=\sqrt{2^2+1^2}=\sqrt{5}.

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

3 0
2 years ago
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