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kogti [31]
3 years ago
14

two companies working together can clear a parcel of land in 9 hours. working alone,it would take company A 3 hours longer to cl

ear the land than it would company B. How long would it take company B to clear the parcel of land alone ( round your answer to the nearest tenth.)​
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

.33

Step-by-step explanation:

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Evaluate the expression for the given value of variable(s)
Olenka [21]
You would: 
(4 * 2 - 4) + (3 - 2^2) + (2 * 2^3)
(8 - 4) + (3 - 4) + (16)
4 + -1 + 16 = 19
8 0
3 years ago
Robyn uses cup of blueberries to make each loaf of blueberry bread. Explain how many loaves of blueberry bread she can make with
tekilochka [14]

Answer:

2 loaves of blueberry bread

Step-by-step explanation:

for 1 loaf of bread she uses 1 cup

for 2 loaves she will use 2 cupa

7 0
3 years ago
Please help. Evaluate 5(n+3)-7n , when n = 6
never [62]

Answer:

3

Step-by-step explanation:

because if N = 6, then you will have to substitute the n to n and then do the order of operation. first it will be 6+3=9 and then 9*5=45. then you will do 7*6=42 and then subtract 45-42=3

5 0
3 years ago
Read 2 more answers
Please help, it’s urgent !
g100num [7]

Answer:

f(-10) = 2 times -10 + 1

= -19

f(2) = 2^2

= 4

f(-5) = 2 times -5 + 1

= -9

f(-1) = (-1)^2

= 1

f(8) = 3-8

= -5

Step-by-step explanation:

5 0
3 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
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