Step-by-step explanation:
(a×b^-3×c^-3)⁵ / (a^-3×b⁴×c⁴)^-5
let's look at the numerator (the top) first :
a⁵×b^-15×c^-15
and now the denominator (the bottom) :
a¹⁵×b^-20×c^-20
both divided are (due to the commutative rules of multiplication we can split this first into the parts of the individual variables, and then multiply them all with each other) :
a⁵/a¹⁵ = 1/a¹⁰
b^-15 / b^-20 = b^(-15 ‐ -20) = b⁵
c^-15 / c^-20 = c⁵
so we get as result :
b⁵c⁵/a¹⁰
Answer:
The given set of equation are: x+ (-45) ≤ 35 , x - (-45) ≥ 35
For the given equality to be true, x ≤ 35
Step-by-step explanation:
Here, given the first number = x
Second number = -45
Now, Sum of x and - 45 is at most 35.
⇒ x+ (-45) ≤ 35
Also, The difference of x and -45 is at least 35.
⇒ x - (-45) ≥ 35
Now, simplifying the given set of equations:
x - 45 ≤ 35 ⇒ -x - (-45) > - 35 ( as 3 < 4 ⇒ -3 > -4)
or, -x + 45 > - 35
and second equation is x + 45 ≥ 35
Now, solving both the equations by not taking sign of inequality in to the consideration, we get
x - 45 = 35
x + 45 = 35
Adding both equations,we get: ⇒ 2x = 70
or x = 35
Hence for the given equality to be true, x ≤ 35
Answer:
7 hours
Step-by-step explanation:
We are given that
At sunset, the temperature=-5 degrees Fahrenheit
Each hour, temperature falling=2degrees Fahrenheit
We have to find time taken to reach the temperature -19° F.
Let x be the time time taken to reach the temperature -19° F
According to question
Where we taking 2 negative because temperature decreases.
Hence, it will take 7 hours for the temperature to reach -19° F.
Answer:
Approximately 16.
Step-by-step explanation:
If you just divide 200/12.54, you get about 15.9 which rounds to 16.
Answer:
e = 1/2
Step-by-step explanation:
to solve foe e in this 4/3=-6e-5/3
solution
4/3=-6e-5/3
4/3 + 5/3 = 6e
find the lcm of the left hand side
4 + 5/3 = 6e
9/3 = 6e
cross multiply
3 x 6e = 9 x 1
18e = 9
divide both sides by the coefficient of e which is 18
18e /18 = 9/18
e = 1/2
therefore the value of e in the expression above is evaluated to be equals to 1/2
