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chubhunter [2.5K]
3 years ago
9

6x - 8y = 12 and 5x + 8y = -1 Solve using elimination​

Mathematics
2 answers:
arsen [322]3 years ago
8 0

Answer:

(1,-3/4)

Step-by-step explanation:

Luckily, y is already opposites, so it should be easier:

6x-8y=12

5x+8y=-1    

Combine; This should end up with y eliminated -

11x = 11

x = 1

Now we can plug 1 in for x in one of the equations to find y. I'm going to use the second one.

5(1) +8y = -1

5+8y=-1

8y=-6

y=-6/8 (you can simplify)

The point at which the lines intersect is (1,-3/4)

Setler [38]3 years ago
6 0

Answer:

Step-by-step explanation:

6x-8y=12

5x+8y=-1

add them

11x=11

x=1

y=-3/4

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2(3 – 4a) + 5(a – 7)
PilotLPTM [1.2K]

Answer:

The answer is -(29+3a).

Step-by-step explanation:

=2(3-4a)+5(a-7)

= 6- 8a +5a -35

= 6-35-8a+5a

= -29-3a

= -(29+3a)

<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em>

6 0
3 years ago
Read 2 more answers
A rectangle has a perimeter 204 it’s length six feet longer than twice it’s width if L stands for the rectangle and W stands for
andriy [413]

Answer:

W=32

L=70

Step-by-step explanation:

L=2w+6

204=2L+2W

204=2w+2(2w+6)

204=2w+4w+12

192=6w

w=32

L=2(32)+6

L=70

6 0
3 years ago
2x + 4y = 14<br> 3x - 4y = -39
cestrela7 [59]

Answer:

2x + 4y = 14 = x= −2y+7

3x - 4y = -39= x=  4=3 y−13

Step-by-step explanation:

5 0
3 years ago
What are the demensions of a rectangle if the perimiter is 20 and the area is 24
Advocard [28]

Answer:

I simply listed the factors of 24, and tested which ones worked in this equation: P = 2a + 2b.

So the factors listed were:

24 x 1

12 x 2

8 x 3

6 x 4

After testing each one of these, 6 and 4 had worked for me.

P = 2(6) + 2(4)

P = 12 + 8

P = 20

Therefore, the dimensions of this rectangle are 6 and 4.

Step-by-step explanation:

3 0
2 years ago
answer it its a easy pionts no links or ill report u and u will not get brianly anymore pease answer it plsssss​
Norma-Jean [14]

Answer:

8:112 third blank put 14

6 0
3 years ago
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