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2 years ago

Subtract. (11x2+3x−9)−(2x2+2x+7)

Mathematics

1 answer:

Alexeev081 [22]2 years ago

4 0

Answer:

-267

Step-by-step explanation:

this is because 11 ×2=22,22+3=25,25×-9= -225 and then the other bracket when I solved I had 42 and so -225-42 = -267

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Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

7 0

2 years ago

There are 16 sixth graders and 20 seventh graders in the Robotics Club. For the first project, the club sponsor wants to organiz

polet [3.4K]

Because you cannot add the two numbers you must find a common denominator for 16 and 20. This answer is 4. The greatest number of group members possible is 4.

7 0

3 years ago

Tony’s tattoo parlor sold 389 tattoos this month. 43 of those tattoos where arm tattoos. What is the reasonable estimate of the

qaws [65]

Answer:89%

Step-by-step explanation: its the probability that they will get anything other than an arm tattoo. So you subtract 43 from 389 and it gives you 346,

346/389 x 100% = 88.9%

4 0

3 years ago

Read 2 more answers

A manager wants to select one group of 4 people from his 28 assistants.

Keith_Richards [23]

There are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

A manager wants to select one group of 4 people from his 28 assistants.

The total number of groups possible = C(28, 4)

$= \rm \dfrac{28!}{4!(28-4)!}$

After calculating:

= 20475

Thus, there are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

8 0

1 year ago

Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability

krok68 [10]

Answer:

$P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}$

Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

$P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}$

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$

So for this case we can solve for P(A) like this:

$P(A) = 1-P(A') = 1-\frac{68}{73}=\frac{5}{73}$

And now we can find $P(A \cup B)$ using the total probability rul given by:

$P(A \cup B) = P(A)+P(B) -P(A \cap B)$

And if we replace the values given we got:

$P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}$

And that would be the final answer.

5 0

2 years ago