Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
Answer:
A≈149.84
Step-by-step explanation:
A=a2+2aa2
4+h2=62+2·6·62
4+92≈149.842
Answer:
the whole page????
Step-by-step explanation:
am confusion
Answer:
366.7424164 feet
Step-by-step explanation:
330x160
Use pythag theorem
a²+b²=c²
330²+160²=c²
c=366.7424164 feet