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Margarita [4]
3 years ago
6

Using this illustration, what is the chemical formula? Picture and possible answers are below.

Chemistry
2 answers:
qwelly [4]3 years ago
4 0
NH3. 1 nitrogen and 3 hydrogen
aleksandrvk [35]3 years ago
3 0

The answer is It is NH3.....

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A helium filled weather balloon has a volume of 806 L at 20.9°C and 753 mmHg. it is released and rises to an altitude of 6.8 km,
OLEGan [10]
<h3>Answer:</h3>

1257.45 L

<h3>Explanation:</h3>

We are given;

  • Initial volume of Helium gas, V1 as 806 L
  • Initial temperature of Helium gas,T1 as 20.9°C
  • Initial pressure of Helium gas, P1 as 753 mmHg
  • Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
  • Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C

But, K = °C + 273.15

Therefore, T1 = 294.05 K and T2 = 254.05 K

  • We are required to calculate the new volume of the balloon at 6.8 km.
  • To determine the new volume we are going to use the combined gas law.
  • According to the combined gas law, \frac{P1V1}{T1}=\frac{P2V2}{T2}

Thus, rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(753)(806L)(254.05K)}{(417)(294.05)}

V2=1257.45L

Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L

7 0
3 years ago
What is the molecular formula of paradichlorobenzene that has a molar mass of 147.g/mol and an empirical formula of C3CIH2?
Gwar [14]

Answer:

the molecular formula of paradichlorobenzene is C6H4CL2

6 0
3 years ago
A match burns because of what type(s) of properties?
GalinKa [24]
It would be a chemical property
4 0
4 years ago
Read 2 more answers
According to Boyle’s Law, if temperature and number of gas particles are held constant, what happens to the pressure of a system
larisa86 [58]
The pressure increases if the volume decreases
3 0
3 years ago
A 10.0-milliliter sample of NaOH(aq) is neutralized by 40.0 milliliters of 0.50 M HCl. What is the molarity of the NaOH(aq)?
Ludmilka [50]
\frac{10 mL}{1000 mL}  = 0.01 L

\frac{40mL}{1000mL} =0.04L

M _{1} V_{1}=M_{2}V_{2}

M_{1}(0.01)=(0.50)(0.04)

M_{1}(0.01)=0.02

M_{1}= \frac{0.02}{0.01}

M_{1}=2
3 0
4 years ago
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