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USPshnik [31]
3 years ago
10

How many atoms of phosphorus are in a 0.859 g sample? Answer in units of atoms.

Chemistry
1 answer:
bekas [8.4K]3 years ago
3 0
Moles = Mass(g) / ar
Moles of phosphorus = 0.859 / 31
= 0.0277096774

1 mole = 6.02 × 10^23

Atoms of phosphorus = 0.0277096774 × 6.02×10^23
=ans.

sorry i cant do the calculation. I dont have a calculator with me.
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Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.
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The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C          40.6       12                   \frac{40.6}{12} = 3.3                        \frac{3.3}{3.3} = 1

H          5.1          1                      \frac{5.1}{1} = 5.1                          \frac{5.1}{3.1} = 2

O         54.2       16                    \frac{54.2}{16} = 3.3                        \frac{3.3}{3.3} = 1

The Empirical formula of compound is C₁H₂O₁ or CH₂O

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}

   = \frac{118.084}{30}

   = 4

Molecular formula = n × Empirical formula

                              = 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

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