Question

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Answer 1

Answer:

1) C = 3

2) B = 5

3) C = 8

Step-by-step explanation:

Question 1)

We have:

$(2x+3)(4x-1)$

Distribute:

$=(2x+3)(4x)+(2x+3)(-1)$

Distribute:

$=8x^2+12x-2x-3$

Combine like terms:

$=8x^2+10x-(3)$

Therefore, C = 3.

Question 2)

We have:

$(x+2) (2x^2+x-1)$

Distribute:

$\displaystyle =(x+2)(2x^2)+(x+2)(x)+(x+2)( - 1)$

Distribute:

$=(2x^3+4x^2)+(x^2+2x)+(-x -2)$

Combine like terms:

$=2x^3+(5)x^2+x-2$

Therefore, B = 5.

Question 3)

We have:

$(x+2)(x^2-3x-2)$

Distribute:

$=(x+2)(x^2)+(x+2)(-3x)+(x+2)(-2)$

Distribute:

$=(x^3+2x^2)+(-3x^2-6x)+(-2x-4)$

Combine like terms:

$=x^3-x^2-(8)x-4$

So, C = 8.