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Allushta [10]
3 years ago
9

Trey is conducting an experiment to determine which fish food causes the most goldfish activity over a period of two weeks. He i

s going to set up ten fish tanks with 4 goldfish each. He will feed the fish in half of the tanks Swift Salmon food and the fish in the other half of the tanks Fast Flounder food. He will expose them to direct sunlight for 4 hours per day. Each tank will have the same size and type of goldfish, which will be fed the same amount of fish food. Each tank will be filled with the same type and amount of water and with the same type and amount of river rock.
Physics
2 answers:
mr_godi [17]3 years ago
8 0

Answer:

This question is incomplete as it lacks options, the options are:

Which change would be the most effective way to improve the validity of this experiment?

A) Increase the number of goldfish in each tank.

B) Increase the daily amount of food for each tank.

C) Create another group that is fed regular fish food.

D) Increase the number of tanks in each treatment group.

The answer is C

Explanation:

According to this question, an experiment is conducted by Trey to determine which fish food causes the most goldfish activity over a period of two weeks. In this experiment, the independent variable is the FISH FOOD which are; Swift Salmon food and Fast Flounder food. Other variables such as type of gold fish, amount of fish food, amount & type of water etc.

One of the ways to improve an experiment, which is lacking in this case is to have a CONTROL GROUP. Based on the fish foods used for each group, it is obvious that all groups in this experiment are experimental. Hence, creating another group that is fed regular fish food will serve as the CONTROL GROUP in order to compare with the experimental groups. This will improve the validity of the experiment.

PolarNik [594]3 years ago
3 0

Answer:

The answer for this question is answer C-  

Explanation:

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Two golf balls are hit from the same point on a flat field. Both are hit at an angle of 55 degree above the horizontal. Ball 2 h
juin [17]

Answer:

d_2 = 4d_1

Explanation:

The range or horizontal distance covered by a projectile projected with a velocity U at an angel of θ to the horizontal is given by

R = U²sin2θ/g

Let the range or horizontal distance of ball 1 with initial velocity U projected at an angle θ = 55° be

d_1 = U²sin2θ/g

Let the range or horizontal distance of ball 2 with initial velocity V = 2U projected at an angle θ = 55° be

d_2 = V²sin2θ/g

= (2U)²sin2θ/g

= 4U²sin2θ/g

= 4d_1   (since d_1 = U²sin2θ/g)

So, the ball 2 lands a distance d_2 = 4d_1 from the initial point.

4 0
3 years ago
A 500 N force accelerates an object at 20 m s-2. What is its mass?
avanturin [10]

<u>Answer</u>: The mass of the object is 25kg.

The given question deals with Newton's second law of motion and its applications.

<u>Explanation:</u> Given force, F=500N

                                 acceleration, a=20 m/s^{2}

  From Newton's 2nd law of motion , we have

                             F=ma where m=mass of the object

                         ⇒500=m×20

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                 ∴ Mass of the object is 25 kg .

<u> </u><u>Reference Link: </u>brainly.com/question/1141170

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Hatshy [7]

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3 years ago
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Answer:

Force=7.71KN in the opposite direction

Explanation:

Given the mass of the car(M)=1000Kg

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we know that 1km/hr=5/18 m/sec

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F=1000* 7.712=7712N=7.71KN

6 0
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