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3 years ago

A huge, jagged rock sits atop a windy cliffside. Over a period of many years, how will the rock MOST LIKELY change?

Physics

2 answers:

sweet-ann [11.9K]3 years ago

6 0

Answer:

Option (D)

Explanation:

Wind erosion will take place extensively as the cliff-side is exposed on the outcrop. Due to the wind erosion, the large, jagged rock will undergo the process of weathering where the softer parts of the rock will be eroded much rapidly in comparison to the harder parts, as a result of which the overall size of the rock will decrease and the surface will be uneven and somewhat rough. This will take place over a due course of time. The main agent that is responsible for erosion is the wind.

Thus, the given rock will become smaller and less smooth after a definite period of time.

Thus, the correct answer is option (D).

Shtirlitz [24]3 years ago

5 0

It will become smaller and less smooth. Only because with the wind blowing sand or other other small items it will cause the rock to be pelted which will chip the surface, breaking and making the rock small and rougher

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On a spending spree in Malaysia, you buy an ox with a weight of 28.9 piculs in the local unit of weights: 1 picul = 100 gins, 1

Talja [164]

Answer:

1747.41 kg

Explanation:

If 1 piculs = 100 gins,

Then 28.9 piculs = (28.9 × 100) gins = 2890 gins.

Also,

If 1 gin = 16 tahils

then 2890 gins =( 16 × 2890 ) = 46240 tahils

Also,

If 1 tahil = 10 chees,

Then 46240 tahils = 46240 × 10 chees = 462400 chees.

Also,

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Also,

If 1 hoon = 0.3779 g,

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The mass in kg that i will declare in the shipping manifest = (1747409.6/100 )kg = 1747.41 kg

6 0

3 years ago

An elevator cab has a mass of 4710 kg and can carry a maximum load of 1910 kg. If the cab is moving upward at full load at 3.80

OLEGan [10]

Answer:

Power P=246.78 KW

Explanation:

Mass of Elevator=4710 Kg

Can carry load =1910 Kg

Total Mass m to be lifted =4710 kg + 1910 Kg =6620 kg

speed = 3.80 m/s ⇒ per second distance traveled (height h) = 3.80 m and time t = 1 s

Using formula of Power P = $\frac{work}{time}$

P = $\frac{mgh}{t}$

P= 6620kg × 9.81 m/s² × 3.80 m / 1s

P= 246780.36 W

P=246.78 KW

4 0

3 years ago

Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject

Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

$t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}$

where

$\mu_{sun}$ is gravitational parameter of sun = 1.32712 x 10^20 m^3 s^2. $t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}$

t = 12,105.96 sec

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3 years ago

If EMS waves are transverse, what conclusion can you make concerning the distances they can travel?

Svet_ta [14]

Explanation:

The wavelength, λ defined as the total distance traveled by the wave in one full cycle of motion. In other words, wavelength can be given by horizontal distance between repeating units of wave pattern.

Also, the wavelength of a transverse wave can be measured as the distance between two adjacent crests or troughs.

λ × f = v

Where,

f = frequency in Hz

v = speed in m/s

8 0

3 years ago

Compute the voltage drop along a 26-m length of household no. 14 copper wire (used in 15-A circuits). The wire has diameter 1.62

zepelin [54]

Answer:

V= 2.7 [v]

Explanation:

The value of the resistance is given by:

$R=L*\frac{Rho}{A}\\\\where:\\R=resistance\\L=Lenght\\Rho=Resistivity\\A=Transversal -Area$

so:

$R=26m*\frac{(1.68*10^{-8}ohm*m)}{\pi *(\frac{1.628*10^{-3}m}{2})^2}\\R=0.21 Ohm$

We can calulate the voltage dropped using the Ohm's law:

$V=I*R\\V=13A*0.21Ohm=2.7V$

8 0

3 years ago