I believe the correct answer is 0
Step-by-step explanation:
To solve this question, we use an abbreviation formula called BODMAS which is:
B = Brackets
O = Of
D = Division
M = Multiplication
A = Addition
S = Subtraction
We solve each element that is available in the order of the abbreviated letter.
1. We solve the brackets:
2. We solve the second bracket:
The equation now is 
3. We now solve addition first:
4. Now we solve the subtraction:
The answer then = 0
Answer:
the answer is b
Step-by-step explanation:
just got it right on my laptop :)
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
The answer is the last on 12
Answer:
y= -9
Step-by-step explanation:
y+6=-3
subtract 6 from both sides
y=-9
