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kaheart [24]
3 years ago
13

PLEASE HELP ME PLEASE!!

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

A then D then C then F thats what I see

Step-by-step explanation:

erastova [34]3 years ago
5 0

Answer:

Is that you in your pfp?

Step-by-step explanation:

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If r^n=a, then which of the following are true statements? Check all that apply.
Vanyuwa [196]
A. This is correct. When you transfer n to the other side, that would be the reciprocal power of a.

b. This is incorrect, because this contradicts with choice a.

c. This is correct. When a number is raised to a "1/n" fraction, that is equivalent to the nth root of the number.

d. This is incorrect, because it is not equivalent to the given equation.

<em>Thus, the answers are A and C.</em>
3 0
3 years ago
Find the opposite of 1/3 and of -7/12
dimaraw [331]
Opposite number is the same number with the opposite sign:

So the opposite of \frac{1}{3} is -\frac{1}{3}, since the original number is positive

opposite of - \frac{7}{12} is \frac{7}{12}, since the original number is negative

3 0
3 years ago
Read 2 more answers
What does supplementary mean and how do you know if angles are supplementary
IRISSAK [1]

Answer:

Supplementary angles are those angles that sum up to 180 degrees. For example, angle 130° and angle 50° are supplementary angles because sum of 130° and 50° is equal to 180°.

Step-by-step explanation:

6 0
2 years ago
( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 =<br><br> Simplify the exponential expression
Korvikt [17]

Answer:

2

Step-by-step explanation:

\frac{(3*2)^4*3^{-3}}{2^3*3}

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4  * 2^4

\frac{3^4*2^4*3^{-3}}{2^3*3}

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1  are same

\frac{3^1*2^4}{2^3*3^1}

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2



4 0
3 years ago
The function f(x) = x2 is reflected across the x-axis and a stretch factor of 4 is applied to create a second function, g(x). Wh
iren [92.7K]
Well, if we see the graph of x^2
the vertex is (0,0)
if we reflect it acrosss the x axis, teh vertex is still (0,0)
verteical strech doesn't change the vertex

vertex of g(x) is same as f(x)

first answer
7 0
3 years ago
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