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kupik [55]
3 years ago
8

Joseph buys a watermelon that weighs 5%

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

The watermelon weighs 2,500 grams more than the cantaloupe.

Step-by-step explanation:

Giving the following information:

Watermelon= 5kg

Cantaloupe= 2,500 grams

We know that 1 kilogram equals 1,000 grams.

<u>First, we need to determine the weight of the watermelon in grams.</u>

Watermelon= 5*1,000= 5,000 grams

<u>Now, the difference:</u>

Difference= 5,000 - 2,500

Difference= 2,500 grams

The watermelon weighs 2,500 grams more than the cantaloupe.

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Which of the following expressions is a factor of the polynomial x2−2x−24?
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Answer:

B.

Step-by-step explanation:

The factored version of the expression is:

(x-6)(x+4)

To factor, you want two numbers that multiply together to give you -24 and add together to give you -2

8 0
3 years ago
Suppose that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $500, $250, and $100. How ma
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Answer:

80 distributions of the three scholarship are possible.

Step-by-step explanation:

Given that 4 freshman, 5 sophomore, and 4 juniors have been nominated to receive a scholarship of $ 500, $ 250, and $ 100, to determine how many distributions of the three scholarship are possible if one scholarship is to be awarded to someone from each class you must perform the following calculation:

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Therefore, 80 distributions of the three scholarship are possible.

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3 years ago
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3 years ago
looks out from the crown of the Statue of Liberty, approximately 250 ft above ground. The tourist sees a ship coming into the ha
Zigmanuir [339]

Answer:

The distance from the base of the statue to the ship is 771.60 ft

Step-by-step explanation:

Refer the attached figure

Height of statue AB= 250 feet

The tourist sees a ship coming into the harbor and measures the angle of depression as 18°.

So, ∠ACB = 18°

We are supposed to find the distance from the base of the statue to the ship i.e. BC

In ΔABC

Tan \theta = \frac{Perpendicular}{Base}

Tan 18^{\circ}=\frac{AB}{BC}

Tan 18^{\circ}=\frac{250}{BC}

BC=\frac{250}{Tan 18^{\circ}}

BC=\frac{250}{0.324}

BC=771.60 ft

Hence the distance from the base of the statue to the ship is 771.60 ft

3 0
3 years ago
There is something wrong with the reason. I don’t know what it is. Could someone help me. The picture of the figure is on the ne
stira [4]

9514 1404 393

Answer:

  CPCTC

Step-by-step explanation:

The applicable reason for statement 4 is "Corresponding Parts of Congruent Triangles are Congruent (CPCTC)".

The reason shown in your problem statement is applicable only within one triangle. The segments of interest are in two different triangles.

8 0
3 years ago
Read 2 more answers
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