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Bezzdna [24]
3 years ago
14

A wheel has a constant angular acceleration of 4.5 rad/s2. during a certain 5.0 s interval, it turns through an angle of 128 rad

. assuming that the wheel started from rest, how long has it been in motion at the start of this 5.0 s interval?
Physics
1 answer:
dalvyx [7]3 years ago
3 0
The solution for this problem is through this formula:Ø = w1 t + 1/2 ã t^2 
where:Ø - angular displacement w1 - initial angular velocity t - time ã - angular acceleration 
128 = w1 x 4 + ½ x 4.5 x 5^2 128 = 4w1 + 56.254w1 = -128 + 56.25 4w1 = 71.75w1 = 71.75/4
w1 = 17.94 or 18 rad s^-1 
w1 = wo + ãt 
w1 - final angular velocity 
wo - initial angular velocity 
18 = 0 + 4.5t t = 4 s
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Julli [10]

Answer:

I don't know.

Explanation:

I have no idea what you are referring to.

4 0
1 year ago
Bartek w czasie 2minut przesunął ruchem jednostajnym kamień na odległość 0,5m.Oblicz moc mięśni Bartka jeśli siła oporów wynsiła
Ipatiy [6.2K]

Answer:

Bartek's muscle power = 2.667 W

Moc mięśni Bartka = 2.667 W

Explanation:

English Translation

Bartek within 2 minutes moved the stone

steadily at a distance of 0.5 m. Calculate Bartek's muscle power , if the resistance force was 640N.

The power, P, expended or generated by moving a body to move a velocity, v, against a resistive force, F is given as

P = Fv

P = ?

F = 640 N

v = velocity = (0.5) ÷ (2×60) = 0.00416667 m/s

P = 640 × 0.0041666667 = 2.667 W

In Polish/Po polsku

Moc P, zużyta lub wytworzona przez poruszanie ciałem w celu przemieszczenia prędkości v przeciwko sile oporowej, F jest podawana jako

P = Fv

P = ?

F = 640 N

v = velocity = (0.5) ÷ (2×60) = 0.00416667 m/s

P = 640 × 0.0041666667 = 2.667 W

Hope this Helps!!!

Mam nadzieję że to pomoże!!

4 0
3 years ago
What is the difference between “exercise” and “physical activity”?
Aleksandr-060686 [28]
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4 0
3 years ago
A car and driver weighing 5060N passes a sign stating "Bridge out 27.5 meters ahead." She slams on the brakes and the car decele
OlgaM077 [116]

Answer:

<u>198785.714286 Joules</u>

Explanation:

W=f*d

F=ma\\F=516.326530612*-14\\F=-7228.57142857 N\\

<u>To find work:</u>

Now that the force and the distance are known, plug and chug:

W=f*d\\W=-7228.57142857*27.5\\W=-198785.714286J

Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.

So, your answer is

<u>198785.714286 Joules</u>

6 0
3 years ago
Betelgeuse is 600 ly from Earth Calculate the distance in kilometres
Vesnalui [34]

Answer:

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Explanation:

Recall that 1 lightyear = 9.461 x 10¹² km

hence

600 lightyears

= 600 x 9.461 x 10¹²

= 5.6766 x 10¹⁵

= 5.68 x 10¹⁵ km  (rounded)

3 0
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