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zhannawk [14.2K]
3 years ago
7

hich best explains why no current is induced? The wire needs to be coiled less tightly. The wire needs to be straight, not coile

d. The magnet needs to be moved through the coils of wire. The magnet needs to be held above the coils of wire.
Physics
1 answer:
Dahasolnce [82]3 years ago
7 0
The magnet needs to be held above the coils of wires
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Which technology is most efficient in mapping large areas of the ocean floor?
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''Sonar'' is the answer.
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3 years ago
An 850 kg elevator is accelerating upwards at 3.0 m/s2. Calculate the tension in the cable.
sveta [45]

Answer:

10880N

Explanation:

We are given that

Mass of elevator, m=850 kg

Acceleration, a=3m/s^2

g=9.8m/s^2

We have to find the tension in the cable.

We know that

When elevator is accelerating upward then tension in the cable

T=m(a+g)

Using the formula

T=850(3+9.8)

T=10880N

7 0
2 years ago
A 3-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the a
Kipish [7]

Answer:

Energy, 9 kWh or 32400 kJ

Explanation:

Given that,

The power of heater, P = 3 kW

It runs for 3 hours to raise the water temperature to the desired level. We need to find the amount of electric energy used. We know that the electrical power of an object is given by total energy delivered per unit time. It is given by :

P=\dfrac{E}{t}

E=P\times t

E=3\ kW\times 3\ h

E = 9 kWh

Since, 1 kWh = 3600 kJ

E = 32400 kJ

So, the amount of electric energy used is 9 kWh or 32400 kJ. Hence, this is the required solution.

4 0
3 years ago
An object is dropped from an altitude of one Earth radiusabove Earth's surface. If M is the mass of Earth and R is itsradius the
Montano1993 [528]

Answer:

The speed of the object just before it hits Earth is  \sqrt{\dfrac{GM}{R}}

(A) is correct option.

Explanation:

Given that,

M = mass of earth

R = radius of earth

The potential energy at height above the surface of the earth

P.E=-\dfrac{GmM}{R+h}

The kinetic energy at height above the surface of the earth

K.E = 0

The total energy at height above the surface of the earth

E = K.E+P.E

E = -\dfrac{GmM}{R+h}....(I)

The total energy at the surface of the earth

E'=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}....(II)

We need to calculate the speed of the object  just before it hits Earth

From equation (I) and (II)

-\dfrac{GmM}{R+h}=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}

Here, h = R

-\dfrac{GmM}{2R}=\dfrac{1}{2}mv^2-\dfrac{GmM}{R}

v= \sqrt{\dfrac{GM}{R}}

Hence, The speed of the object just before it hits Earth is  \sqrt{\dfrac{GM}{R}}.

4 0
3 years ago
Which of the following is a vector quantity?
lutik1710 [3]

Since vectors are essentially quantities that have direction, D must be the answer as it contains a direction (down) while the other ones do not.

6 0
3 years ago
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