Convection cell that occurs at the lowest latitudes is called the Hadley cells. This is an atmospheric convection cell which is large-scale. The air rises at the equator and sinks at the medium latitudes which are 30 degrees north or south.
Answer:
a. the density will not change
b. D' = 0.125 D
So, the density will change by a factor of 0.125
Explanation:
a.
Density is the material property and the value of density is constant for all solid materials. So, when the dimensions of the a solid are increased, while the material is same, then the material must be added to the object for increasing its dimensions. So, with the increase in the volume, the mass of the object also increases. And as a result the density of the object remains constant.
Since, here the material remains the same.
<u>Therefore, the density will not change</u>
<u></u>
b.
Density = mass/Volume
D = m/V ------------ equation (1)
Now,
V = LWH ----------- equation (2)
Now, if each dimension increases by a factor of 2, the volume becomes:
V' = (2L)(2W)(2H)
V' = 8 LWH
using equation (2)
V' = 8 V
So, for constant mass, density becomes:
D' = m/V'
D' = m/8V
using equation (1)
D' = D/8
<u>D' = 0.125 D</u>
<u>So, the density will change by a factor of 0.125</u>
Answer:
τ ≈ 0.90 N•m
F =
Explanation:
I = ½mR² = ½(10)0.5² = 1.25 kg•m²
α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²
τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m
τ = FR
Now we have the unanswered question of reference frame.
80° from what?
If it's 80° from the radial
F = τ/Rsinθ = 0.90/0.5sin80 = 1.818... ≈ 1.8 N
If it's If it's 80° from the tangential
F = τ/Rcosθ = 0.90/0.5cos80 = 10.311... ≈ 10 N
There are an infinite number of other potential solutions
Unf there's no diagram. but this looks like a sort of celsius to fahrenheit temp scale conversion sort of problem.
