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Helga [31]
3 years ago
9

A 2 kg block slides on a rough horizontal surface with muk=0.6. It has an initial velocity of 5 m/s. Use g = 10 m/s2

Physics
1 answer:
Irina18 [472]3 years ago
4 0

Answer:

360000

Explanation:

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Using the rules for significant figures, what do you get when you multiply 67.6 by 1.2?
Paul [167]

Answer:

B. 81

Explanation:

When you multiply two numbers, round the answer to the least number of significant figures available.  67.6 has three significant figures, and 1.2 has two significant figures.  So we round to two significant figures.

3 0
3 years ago
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Determine the change in thermal energy of 100 g of copper (M = 63,5, Debye 348K) if it is cooled from
Setler [38]

Answer:

given,

mass of copper = 100 g

latent heat of liquid (He) = 2700 J/l

a) change in energy

Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (300 - 4)

Q = 11153.63 J

He required

Q = m L

11153.63 = m × 2700

m = 4.13 kg

b) Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (78 - 4)

Q = 2788.41 J

He required

Q = m L

2788.41 = m × 2700

m = 1.033 kg

c) Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (20 - 4)

Q = 602.90 J

He required

Q = m L

602.9 = m × 2700

m =0.23 kg

8 0
4 years ago
Buna! Am nevoie urgent va rog de ajutor la aceste 2 ex:
Gemiola [76]

Explanation:

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7 0
3 years ago
(Don't answer unless you know a lot about tf2 cod, and etc. Ty)
aev [14]
What about cod my guy which one are we talking ?
7 0
3 years ago
1 point
Darya [45]

Given that,

Mass of object, m = 55 kg

Mechanical energy of the object, M = 4306 J    

Potential energy, P = 2940 J

We know that the mechanical energy is the sum of kinetic and potential energy such that,

Mechanical energy = kinetic energy + potential energy

K=M-P\\\\K=4306-2940\\\\K=1366\ J

Kinetic energy is given by :

K=\dfrac{1}{2}mv^2v is velocity of object

v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1366}{55}} \\\\v=7.04\ m/s

So, the velocity of object is 7.04 m/s.            

7 0
3 years ago
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