Answer:
400 trips
Explanation:
Mechanical energy needed to climb 14 m by a man of 68 kg
= mgh
= 68 x 9.8 x 14
= 9330 J
1 Kg of fat releases 3.77 x 10⁷ J of energy
.45 kg of fat releases 1.6965 x 10⁷ J of energy
22% is converted into mechanical energy
so 22% of 1.6965 x 10⁷ J
= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.
one trip of climbing of 14 m requires 9330 J of mechanical energy
no of such trip possible with given mechanical energy
= 3732.3 x 10³ / 9330
= 400 trips
Answer:
D gravity
Explanation:
please mark me brainliest
"The rock has a downward acceleration of 9.8 m/s2" is the one among the following choices that explains the <span>rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero). The correct option among all the options that are given in the question is option "D". </span>
28.1 grams is 0.0281 kg.
43.278 kg - 0.0281 kg = 43.2499 or if you round -> 43.250
Answer:
36.9 m/s
Explanation:
From;
v^2 = u^2 + 2as
Where;
v = final velocity =?
a = acceleration = 3.4 m/s^2
u = initial velocity = 0 m/s
s = distance covered = 200 meters
v^2 = 0^2 + 2 * 3.4 * 200
v^2 = 1360
v = √1360
v = 36.9 m/s
