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sdas [7]
3 years ago
11

2. Explain how the graph of x > 5 is different from the graph of x 5.

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

Step-by-step explanation:

The graph of x = 5 is a solid, vertical line through (x,0).

The graph of x > 5 is a dotted, vertical line through (5,0) , and the area to the right of the dotted line is shaded.

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Angle relationships with parallel lines
bekas [8.4K]

Answer:

<h3>X=180 degree</h3>

<h3>X=180-103</h3>

<h3>X=77 degree </h3>

<h3>Hope it helps u</h3>

7 0
3 years ago
How would you solve this? help.
Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

d=\sqrt{(1-5)^2+(-1-7)^2}

d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}

The radius of C is d/2:

r =4\sqrt{5}/2 = 2\sqrt{5}

Center: (3,3)

Radius: 2\sqrt{5}

8 0
3 years ago
A man buys s T-shirt at $p each and sells them at $q each. Find his profit in terms of s , p and q.
SCORPION-xisa [38]

Answer:

What are the options?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If RT = 6 and RS = 9, then RX =<br> A - sqrt(54)<br> B - 13.5<br> C - 7.2<br> D - 4
wolverine [178]

Answer:

Option D RX=4 units

Step-by-step explanation:

we know that

<em>In the right triangle RTS</em>

The cosine of angle TRS is equal to

cos(TRS)=RT/RS

substitute

cos(TRS)=6/9 -----> equation A

<em>In the right triangle RTX</em>

The cosine of angle TRX is equal to

cos(TRX)=RX/RT

substitute

cos(TRX)=RX/6 -----> equation B

∠TRS=∠TRX -----> is the same angle

Match equation A and equation B

6/9=RX/6

RX=6*6/9=4 units

5 0
3 years ago
Help plz<br> I am so confused
ankoles [38]

The answer to number 18 is -  0.25 or 1/4


If you need help with the other ones ask.


<em>Hope this will help :)</em>

8 0
3 years ago
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