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bazaltina [42]
3 years ago
12

What is 3c-9d+7c+5d simplified

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

3c-9d+7c+5d becomes this when it is simplified  10c - 4d

Step-by-step explanation:

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Use the equation xy= 12.6. Find the value of y when x=7
Marat540 [252]

Answer: y = 1.8

Step-by-step explanation:

xy = 12.6   If x is 7  but 7  in the equation for x

7y = 12.6   Divide both sides by 7

y = 1.8  

6 0
3 years ago
Solve for x<br><br> 2/7x = 6<br><br> (SHOW YOUR WORK)
castortr0y [4]

Answer:

The answer to your question is  x = 21

Step-by-step explanation:

Equation

                                       \frac{2}{7} x = 6

- Multiply both sides by 7

                                        \frac{(2)(7)x}{7} = 6(7)

- Simplify

                                        2x = 42

- Divide both sides by 2

                                         \frac{2x}{2} = \frac{42}{2}

- Simplify

                                         x = 21

5 0
3 years ago
Read 2 more answers
Someone help me please
Alika [10]

Answer:

x = 58°

Step-by-step explanation:

The sum of the angles in Δ AHI = 180 , then

∠ AIH = 180° - (66 + 56)° = 180° - 122° = 58°

x and ∠ AIH are corresponding and are congruent , then

x = 58°

7 0
3 years ago
Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
2 years ago
What is 3/4 divided by 1/24
Musya8 [376]
Dividing fractions is the same thing as multiplying by the reciprocal

3/4 x 24/1 = 18
7 0
3 years ago
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