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yan [13]
3 years ago
6

Hiiiii everyoneejhfgwds,ncxzmjke,sdfzxckjh,nm

Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0
Hi lol sohsownqjsududidowlw d
Vesnalui [34]3 years ago
3 0

hello my fellow human how are you O(∩_∩)O

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Consider the region bounded by
Montano1993 [528]
The equation is a circle centered at the origin with radius 8 (sqrt(64))
Therefore, the bounded region is just a quarter circle in the first quadrant.

Riemann Sum: ∑⁸ₓ₋₋₀(y²)Δx=∑⁸ₓ₋₋₀(64-x²)Δx

Definite Integral: ∫₀⁸(y²)dx=∫₀⁸(64-x²)dx
4 0
3 years ago
Simplify 6 - 4[x + 1 - (y + 3)] + 5y
mezya [45]
-4x+9y+14 is the answer to the problem
3 0
3 years ago
What is the volume of the prism?​
jeka94

Answer:

The answer is 24 be

Step-by-step explanation:

cause if we multiply 4 by 3, (which is the square), by the 2 next to it gives 24

8 0
3 years ago
Read 2 more answers
Calculate the distance between the points L = (1, -3) and P = (8,– 7) in the coordinate plane.
mylen [45]

The exact distance between two points L=(1,-3) and P=(8,-7)is 8.062 units, is obtained by formula and graphical method.

Step-by-step explanation:

The given is,

         Two points are L=(1,-3) and P=(8,-7)

Step:1

         By graphical method,

                  First point L (1,-3)

                             The values of x=1 and y=-3 noted in the graph

                 Second point P(8, -7)

                             The values of x=8 and y=-7 noted in the graph

         Now join the points L and P, in the graph,

                           Distance between two points are 8.1 units

                                            ( OR )

Step:2

         By formula method,

                   Distance = \sqrt{(x_{2}-x_{1})  ^{2}+ (y_{2}-y_{1} ) ^{2}  }

        Where,

                 L (1,-3) are (x_{1}, y_{1})

                 P (8,-7) are (x_{2}, y_{2})

        Substitute the values,

                                  = \sqrt{(8-1)  ^{2}+ (-7+3 ) ^{2}  }

                                  = \sqrt{(7)  ^{2}+ (-4 ) ^{2}  }

                                  = \sqrt{49+ 16  }

                                  = \sqrt{65}

                 Distance = 8.06225 units

Result:

           The exact distance between two points L=(1,-3) and P=(8,-7)is 8.062 units, is obtained by formula and graphical method.

8 0
3 years ago
M2-5m-14=0<br>quadratic formula​
Sonja [21]

\bf m^2-5m-14=0 ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}m^2\stackrel{\stackrel{b}{\downarrow }}{-5}m\stackrel{\stackrel{c}{\downarrow }}{-14}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ m= \cfrac{ - (-5) \pm \sqrt { (-5)^2 -4(1)(-14)}}{2(1)}\implies m=\cfrac{5\pm\sqrt{25+56}}{2} \\\\\\ m=\cfrac{5\pm\sqrt{81}}{2}\implies m=\cfrac{5\pm 9}{2}\implies m= \begin{cases} 7\\ -2 \end{cases}

3 0
3 years ago
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