(x-h)^2=4p(y-k)
vertex is (h,k)
p is the distance from focus to vertex and distance from vertex to directix (vertex is in middle of directix and focus)
if p is positive, the parabola opens up and the focus is above the directix
if p is negative, the parabola opens down and the focus is below the directix
we see the directix is over the focus (1>-1) so the parabola opens down and p is negative
distance from (5,-1) to y=1 is 2 units
2/2=1
p=-1 since p is negative
1 up from (5,-1) is (5,0)
veretx is (5,0)
(x-5)^2=4(-1)(y-0)
(x-5)^2=-4y is the equation
Answer:
y-5 = 3/2(x-3)
Step-by-step explanation:
The point slope form of the equation of a line is
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y-5 = 3/2(x-3)
300,000 because you have to just multiply 150 by 200
