Answer:
y = 4x -14
Step-by-step explanation:
The required answer form is slope-intercept form, so we need the slope and the y-intercept of the line.
The slope equation is ...
m = (y2 -y1)/(x2 -x1)
m = (10 -2)/(6 -4) = 8/2 = 4
The y-intercept equation is ...
b = y - mx
b = 2 -4(4) = -14
The equation of the line is y = 4x -14.
30 and 13
x-y=17 and x+y=43
x=17+y and x=43-y, so 17+y=43-y
so y=13
43-13=30, so x=30 and y=13
Answer: point estimate = 3.88
Margin of error = 0.63
Step-by-step explanation:
Confidence interval is written in the form,
(Point estimate - margin of error, Point estimate + margin of error)
The sample mean, x is the point estimate for the population mean. Let m represent the margin of error. Since the confidence interval is given as (3.25 , 4.51), it means that
x - m = 3.25
x + m = 4.51
Adding both equations, it becomes
2x = 7.76
x = 7.76/2
x = 3.88
Substituting x = 3.88 into x + m = 4.51, it becomes
3.88 + m = 4.51
m = 4.51 - 3.88
m = 0.63
<span>a.
The radius of earth is about 6400 kilometers. Find the circumference of
a great circle.
Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km
b. Write an equation for the circumference of any
latitude circle with angle theta
As stated, </span><span><span>the
length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a
great circle of Earth times the cosine of the latitude angle</span>:
=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)
Answer: circumference = 40,212.39 cos(Θ) km
c. Which latitude circle has a
circumference of about 3593 kilometers?
Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km
=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad
Answer: 1.48
d. What is the circumference of
the Equator?
</span>
For the Equator Θ = 0°
=> circumference = 40,213.49cos(0°) km = 40,212.49 km
Answer: 40,212.49 km
The 1st graph has vertex in (-3, -3) which can be translated into
Horizontal shift left 3
Vertical shift down 3
Other than that, the graph shows y=x^2 so it wasn't compressed or stretched
The 2nd graph has vertex in (0, 0) which mean there is no vertical and horizontal shift. But the graph is facing down and it was slimmer than y=x^2 graph. When x=1, the result is y=3 which was 3 times more than it supposed to be.
The graph must be:
Reflection across x-axis
Vertical stretch of 3
The 3rd graph has vertex in (3, -3) which can be translated into
Horizontal shift right 3
Vertical shift down 3
Same as the 1st graph, the 3rd graph shows y=x^2 so it wasn't compressed or stretched.
