Answer: 1.58 hours
<u>Step-by-step explanation:</u>
I believe that it is 24.99 but I'm not too sure. Anyways I hope I helped!
Answer:
17% of the bill
Step-by-step explanation:
Well to find the answer to this question we first have to add 35 + 48 to get the total percent of the bill that Michelle and Lori paid.
35 + 48 = 83%
now that we know the percent of the bill that Lori and Michelle are paying we have to subtract that amount by 100% to get the percent of the bill that Patti is paying.
100% - 83% = 17%
So Patti is paying 17% of the bill
If we wanted to go even farther and find out what 17% of the bill was all we would have to do is multiply 45 by 17% or 45 x 0.17
45 x 0.17 = 7.65
So Patti is paying 7 dollars and 65 cents
Answer:
$8.4375 per game
Step-by-step explanation:
From. The picture attached :
Season long Ticket cost for the bleachers sitting area is : $810
Given that the number of home games in a season is 96
The cost per unit of game could be calculated as :
Cost of season long Ticket / number of home games
= $810 / 96
= $8.4375
$8.4375 per game
Answer:
Step-by-step explanation:
Hello!
X: Cholesterol level of a woman aged 30-39. (mg/dl)
This variable has an approximately normal distribution with mean μ= 190.14 mg/dl
1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:
P(Z≥z₀)= 0.093
-*or*-
P(Z≤z₀)= 0.907
Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:
P(Z≤z₀)= 0.907
Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:
z₀= 1.323
2.
Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:
Z= (X- μ)/δ ~N(0;1)
Z= (X- μ)/δ
Z*δ= X- μ
δ=(X- μ)/Z
δ=(240-190.14)/1.323
δ= 37.687 ≅ 37.7 mg/dl
I hope it helps!
