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3 years ago

30% of what number is 50? (Round to the nearest whole number)

Mathematics

1 answer:

il63 [147K]3 years ago

5 0

Hey ! i’m pretty sure it’s 166 :)

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In a Monopoly market, a firm is a price maker since there are no close substitutes to the product. You are asked to find the com

rewona [7]

ATC= TC/ Q
Avc= vc/q
Afc= Fc/ q
Mc= Change TC/ change q
Tc= vc+ fc
Vc= tc/ fc
Mr= change tr/ change q
P≠ mr

3 0

3 years ago

vredina [299]

No, the sequence is algebraic.

7 0

3 years ago

What is 9,380 divided by 31

s344n2d4d5 [400]

It is 302 remainder 18

5 0

3 years ago

A company that has 350000 shares declares an annual gross profit of $2450665, pays 18.5% of this in tax, and reinvests 25% of th

podryga [215]

Gross profit, G = $2450665

Tax, t=18.5%

reinvestment, r = 25%

Total dividends

= G(1-t)(1-r)

=2450665*(1-0.185)(1-0.25)

=1497968.98

Dividend per share

=1497968.98/350000

=4.280

Earnings per share

EPS = Net profit / number of shares

= 2450665(1-0.185)/350000

=5.7065

Current price = 43.36

P/E ratio

= Current price/EPS

= 43.36/5.7065

= 7.598

=7.6 to one decimal place.

8 0

2 years ago

Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?

spayn [35]

Answer with explanation:

Let us assume that the 2 functions are:

1) f(x)

2) g(x)

Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that

$\frac{d}{dx}\cdot f(x)$

Now the sum of the 2 functions is shown below

$y=f(x)+g(x)$

Diffrentiating both sides with respect to 'x' we get

$\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\$

Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus

$\frac{dy}{dx}$

Thus the sum of the 2 functions is also a concave function.

Part 2)

The product of the 2 functions is shown below

$h=f(x)\cdot g(x)$

Diffrentiating both sides with respect to 'x' we get

$h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)$

Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.

8 0

3 years ago