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arlik [135]
3 years ago
13

In ΔMNO, the measure of ∠O=90°, the measure of ∠N=70°, and OM = 3.3 feet. Find the length of MN to the nearest tenth of a foot.

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0

Answer:

Side MN = 3.5

Step-by-step explanation:

Side NO  = 1.2011

Side OM = 3.3

Side MN = 3.51179

Angle ∠M = 20° = 0.34907 rad = π/9

Angle ∠N = 70° = 1.22173 rad = 7/18π

Angle ∠O = 90° = 1.5708 rad = π/2

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Write a rule for the nth term of the geometric sequence if r = 1/4 and a3 = 2.
GarryVolchara [31]

Answer:

a_{n} = 32(\frac{1}{4})^{n-1}

Step-by-step explanation:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

This means that for example:

a_{3} = a_{1}r^{3-1}

So

a_{3} = a_{1}r^{2}

2 = a_{1}(\frac{1}{4})^{2}

2 = \frac{a_{1}}{16}

a_{1} = 32

Then

a_{n} = 32(\frac{1}{4})^{n-1}

4 0
3 years ago
How many zeros does this polynomial function, y=(x-8)(x+3)^2
lidiya [134]

Answer:

3

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
If 2(x + 3) = x + 10, then x equals what
Rama09 [41]

Answer:

x=4

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You need to apply the Distributive property on the left member of the equation:

2(x + 3) = x + 10\\ 2x+6=x+10

2. Now, you must solve for x, as following:

2x-x=10-6\\ x=4


8 0
3 years ago
Write a reciprocal function with asymptotes x=4 and y=-9.
gayaneshka [121]
Attached the solution and work.

5 0
3 years ago
Ship A and Ship B are 120 km apart when they pick up a distress call from another boat. Ship B estimates that they are 70 km awa
oksian1 [2.3K]

Answer:

147.5 km and 64.4 km

Step-by-step explanation:

a=120  km

b=70  km

β=28 degrees ( ∘)

 

b^2=(a^2)+(c^2)−2ac*cosβ  

70^2 =(120^2 )+(c^2)−2⋅ 120⋅ c⋅ cos(28∘ )  

 (c^2 ) −211.907c+9500=0  

 

note p, q, and r are replacement variables in the Pythagorean theorem since a, b, and c are already in use

p=1;q=−211.907;r=9500  

D=(q^2 ) −4pr=(211.907^2 )−4⋅1⋅9500=6904.75561996  

D>0  

 

c_{1,2}  =   (−q±  \sqrt{D}   )/2p=(211.91±\sqrt{6904.76})/2

​c_{1,2}  =105.95371114±41.5474295834  

(c_{1}−147.501140726)(c_{2}−64.4062815596)=0

c_{1}=147.501140726  

c_{2}=64.4062815596  

5 0
3 years ago
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