Answer:
The answer is milligram, glad to help
Step-by-step explanation:
Answer:
37.69 (≈ 38 ft²)
Step-by-step explanation:
2πr = 30.77
r = 30.77 / (2 * 3.14) = 4.9
half of free-throw circle area: πr² / 2 = (3.14 * 4.9²) / 2 = 37.69 (≈ 38 ft²)
Answer:
∠ECD is 110°
Step-by-step explanation:
For a cyclic quadrilateral,
∠ABC + ∠AEC = 180°
Therefore ∠AEC = 180° - 45° = 135°
∠CAE + ∠ACE + ∠AEC = 180° (Angles in a triangle)
Therefore ∠CAE = 180 - 20 - 135 = 25°
∠CAE = ∠CDA = 25° (Base angles of isosceles triangle ΔCAD)
∠CED + ∠AEC = 180°(Sum of angles on a straight line)
Therefore ∠CED + 135° = 180°
∠CED = 180° - 135° = 45°
∠ECD + ∠CED + ∠CDA = 180°
Therefore ∠ECD = 180° - (∠CED + ∠CDA)
∠ECD = 180° - (45° + 25°) = 110°
Therefore, ∠ECD = 110°.
In 1 hour, a machine could make:
![7 \div 4.2](https://tex.z-dn.net/?f=7%20%5Cdiv%204.2%20)
parts
In 28.8 hours, that machine make
![7 \div 4.2 \times 28.8 = 4.8](https://tex.z-dn.net/?f=7%20%5Cdiv%204.2%20%5Ctimes%2028.8%20%3D%204.8)
parts