All categories

3 years ago

PLEASE PLEASE PLEASE HELP PLEAS :( THE SECOND ONE JEJEJEJDD PLEASEEEEEE

Mathematics

2 answers:

krok68 [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Count the line endings in each letter as you write it down.

Sedbober [7]3 years ago

3 0

Answer:

I agree with tonb .Ace,he's/she's right

You might be interested in

Which mathematical symbol would best fill in the blank to compare the two real numbers 2__1.8

katrin [286]

Hello.

The mathematical symbol that would best fill the blank to compare both numbers is '>', which indicates a number is greater than the other.

Hope I helped.

6 0

3 years ago

Read 2 more answers

In an 11 team soccer league, each team plays once what is the total amount of games played?

stich3 [128]

Answer:

Step-by-step explanation:

11 x 2 = 22

22 teams played

4 0

2 years ago

Remember to show work and explain. Use the math font.

MrMuchimi

Answer:

$\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================$

$1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}$

$\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)$

$--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)$

$--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}$

6 0

3 years ago

A research student is working with a culture of bacteria that doubles in size every

ser-zykov [4K]

Answer:

$2^{24}*1000$ bacteria

Step-by-step explanation:

The generic form of an exponential function is: $f(n)=ar^n$ , where a is the initial amount, r is the rate, and n is the time.

In this case, the initial amount is 1000, so a = 1000. Also, the rate is 2 because the culture doubles in size every 5 minutes. However, our n is not just n; it's actually n/5 because the rate is doubling per 5 minutes, not per 1 minute. If it was per 1 minute, then the time would simply be n. Unfortunately, that's not the case here, so the exponent of r should be n/5, where n is the number of minutes that have passed.

Now, we have: $f(n)=1000(2)^{n/5}$

Since n is the number of minutes, we need to convert 2 hours to minutes:

2 hours * 60 min/hour = 120 minutes.

$f(120)=1000(2)^{120/5}=1000(2)^{24}=2^{24}*1000$ $f(120)=1000(2)^{120/5}=1000(2)^{24}=2^{24}*1000$

Thus, the answer is $2^{24}*1000$ bacteria.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Step by step 579÷3 plz i need help

ololo11 [35]

579/3 fist you divid 5 by 3 than you subtract them and get two than you bring down your seven and have 27 divided by 3 and that is 9. than you bring down your last number and than you come up with an answer of 193.

8 0

3 years ago

Read 2 more answers