All categories

2 years ago

Find the difference. (5x2 - 3x + 7) - (3x2 + 4x - 5)

Mathematics

2 answers:

Katena32 [7]2 years ago

7 0

Answer:

16-7x

Step-by-step explanation:

10x-3x+7-6-4x+5

16-7x

ZanzabumX [31]2 years ago

5 0

16-7x
5x-2-3x+7
8x-5
3x2+4x-5
7x-3
16x-7x

You might be interested in

Please help me, tysmm! and no spam or links please it's rlly annoying -_-

san4es73 [151]

The slope is -2/1.
Rise/Run.
Down 2/ Left 1. Because it’s going down, put a negative.

4 0

2 years ago

Why will i be a good role model essay <br>please i need help this is due tomorrow

WITCHER [35]

Answer:

Relate the points down below to yourself and give examples

Step-by-step explanation:

You show confidence and leadership

Being yourself/unique

You speak and interact kindly with everyone

You show respect and concern for others

You give advice to those who need it

You have humility and a willingness to admit mistakes.

You do good things outside of school

7 0

2 years ago

Please help i can not figure it out

Alisiya [41]

To solve this problem you need to figure out the volume of the sipping container, and the volume of the tissue box.
39*19.5*19.5=14,829.75
6.5*6.5*6.5=274.63

In order to figure out how many fits you need to divide
14,829.75/274.63=53.99

The maximum number that you can fit is the box is 53.

Hope this helps

4 0

3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

2 years ago

In a particular card game, the minimum score a player can achieve in a single game is 20, and the maximum score possible in a si

Shalnov [3]

So if we want to know the least amount, we first want to assume the other two games both had a score of 52, so we can say the last one had the least possible.

So if both got 52, the total points would be 104, for two games of 52 points. Since we want 141 points, we therefore want 37 more points to reach 141.

So the least amount of points a player could've scored in one of the games was 37.

5 0

2 years ago