So first we need to find approximately the number of total students.
Rock I would say is about 200 people. Country, 100, Rap, 255, Classical, 64 as said before, and Blues, 80.
So if we add these all up we can find the total students.
200 + 100 + 255 + 64 + 80
699
Now the relative frequency is how many times something appears in a group.
Classical appears 64 times in about 700 people.
So, 64/700, is closest to the 0.9 selection.
Answer:
4 over 3
Step-by-step explanation:
First off, they give you the answer by showing you the Xs being broken down into 3 groups of 4 (4) and the circles being broken down into 3 groups of 3 (3).
We can use elimination since the Xs are the larger and circles are smaller. So using this, 3 over 4 cant be and neither can 9 over 12.
9 over 4 cant work either because going up by 9s and 4s cant get to 12 over 9.
Answer:
The answer is A!!
Step-by-step explanation:
Answer:
The range of the function is represented by
.
Step-by-step explanation:
Let be
, for
. As we notice that
is an inyective function, that is, the inexistence of two or more domain element with the same image, with a monotone behavior, we can obtain the bounds of the range of the function by evaluating the expression:
Lower bound (
)
![f(-2) = -3\cdot (-2)+6](https://tex.z-dn.net/?f=f%28-2%29%20%3D%20-3%5Ccdot%20%28-2%29%2B6)
![f(-2) = 12](https://tex.z-dn.net/?f=f%28-2%29%20%3D%2012)
Upper bound (
)
![f(7) = -3\cdot (7)+6](https://tex.z-dn.net/?f=f%287%29%20%3D%20-3%5Ccdot%20%287%29%2B6)
![f(7) = -15](https://tex.z-dn.net/?f=f%287%29%20%3D%20-15)
The range of the function is represented by ![Ran\{f(x)\} = (-15, 12]](https://tex.z-dn.net/?f=Ran%5C%7Bf%28x%29%5C%7D%20%3D%20%28-15%2C%2012%5D)