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jekas [21]
3 years ago
11

If the resistance of a circuit is 3 ohms, and the voltage produced by the cell in the circuit is 12 volts, what's the magnitude

of the current?
Chemistry
2 answers:
koban [17]3 years ago
7 0

Answer:

<h2>4 A</h2>

Explanation:

The magnitude of the current can be found by using the formula

i =  \frac{v}{r} \\

v is the voltage

r is the resistance

From the question we have

i =  \frac{12}{3}  = 4 \\

We have the final answer as

<h3>4 A</h3>

Hope this helps you

RSB [31]3 years ago
4 0

Answer:

4A

Explanation:

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Type the correct answer in the box. Spell all words correctly.
cluponka [151]

Answer: hey buddy its not "blome" its biome

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3 0
3 years ago
4 Compared to the energy and charge of the electrons in the first shell of a Be atom, the electrons in the second shell of this
Korvikt [17]
Moving the electron away from the nucleus requires energy, so the electrons in the outer shell will have more energy than ones in the inner shell. Electrons always have a charge of -1, so the charge in the inner and outer shell will be the same. Therefore the answer is 3
5 0
4 years ago
Read 2 more answers
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
4 years ago
This liquid metal has more protons than gold, but fewer electrons then thallium.
WITCHER [35]

The number of protons and electrons of an atom is equal and the amount can be obtained by looking at the atomic number of that atom or element.

The atomic numbers are:

Gold = 79

Thallium = 81

 

So we are looking for the element with an atomic number of 80, that is:

Mercury

 

Answer:

<span>Mercury (Hg)</span>

4 0
3 years ago
Which element below is the most reactive? Hydrogen chlorine neon oxygen
trapecia [35]

Answer:

Chlorine

Explanation:

Chlorine has an atomic number of 17 and a configuration of 2, 8, 7. In the outermost shell, it has 7 seven electrons which means that it needs just one more electron to attain an octet configuration in that shell. Therefore it's can react quickly with any nearby nucleophile.

5 0
3 years ago
Read 2 more answers
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