4 Compared to the energy and charge of the electrons in the first shell of a Be atom, the electrons in the second shell of this
2 answers:
The electrons in the second shell of this atom have (3) more energy and the same charge compared to the first shell
<h3>Further explanation </h3>Bohr's atomic model has shown the energy levels of electrons in the path of the atomic shell
The greater the value of n (the atomic shell, the main quantum number), the greater the energy level
In normal circumstances, electrons fill the shell at the lowest energy level starting from the shell K, L M and then N
When an atom gets energy from outside, the electrons will absorb energy so it moves to higher energy. This situation is called excited
Electrons will return to the original path or a lower energy level because the excited state is unstable. In this condition, the electron will release energy
The electron energy at the nth path can be formulated:
Rh = constant 2.179.10⁻¹⁸ J
So the electron transfer energy (ΔE)
ΔE = E end - E initial
From the electron transfer available, because the value of the Rh constant is the same, the effect is the value of n (shell) ⇒ 1 / n²
Electron configuration of Be (Beryllium) with atomic number 4
1s² 2s² or [He] 2s²
So in the first shell E = -1(n=1), the second shell E = -1/4 (n=2)
So the energy value in the second shell is greater than the first shell
While the electron charge is still the same(-1) (such as protons with + charges and neutrons with neutral charges / 0)
<h3>Learn more </h3>
statement about electrons and atomic orbitals
Effective nuclear charge
statement about subatomic particles is true
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Solid KMnO₄ needed = 7.9 g
<h3>Further explanation</h3>Given
MW KMnO₄ = 158 g/mol
500 mL(0.5 L) of a 0.1M stock solution of KMnO₄
Required
solid KMnO₄
Solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Input the value :
n = M x V
n = 0.1 M x 0.5 L
n = 0.05 mol
Mass KMnO₄ :
= mol x MW
= 0.05 x 158 g/mol
= 7.9 g