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BlackZzzverrR [31]
4 years ago
10

4 Compared to the energy and charge of the electrons in the first shell of a Be atom, the electrons in the second shell of this

atom have
(1) less energy and the same charge
(2) less energy and a different charge
(3) more energy and the same charge
(4) more energy and a different charge
Chemistry
2 answers:
Korvikt [17]4 years ago
5 0
Moving the electron away from the nucleus requires energy, so the electrons in the outer shell will have more energy than ones in the inner shell. Electrons always have a charge of -1, so the charge in the inner and outer shell will be the same. Therefore the answer is 3
Papessa [141]4 years ago
5 0

The electrons in the second shell of this atom have (3) more energy and the same charge compared to the first shell

<h3>Further explanation </h3>

Bohr's atomic model has shown the energy levels of electrons in the path of the atomic shell

The greater the value of n (the atomic shell, the main quantum number), the greater the energy level

In normal circumstances, electrons fill the shell at the lowest energy level starting from the shell K, L M and then N

When an atom gets energy from outside, the electrons will absorb energy so it moves to higher energy. This situation is called excited

Electrons will return to the original path or a lower energy level because the excited state is unstable. In this condition, the electron will release energy

The electron energy at the nth path can be formulated:

\rm En=\dfrac{-Rh}{n^2}

Rh = constant 2.179.10⁻¹⁸ J

So the electron transfer energy (ΔE)

ΔE = E end - E initial

From the electron transfer available, because the value of the Rh constant is the same, the effect is the value of n (shell) ⇒ 1 / n²

Electron configuration of Be (Beryllium) with atomic number 4

1s² 2s² or [He] 2s²

So in the first shell E = -1(n=1), the second shell E = -1/4 (n=2)

So the energy value in the second shell is greater than the first shell

While the electron charge is still the same(-1) (such as protons with + charges and neutrons with neutral charges / 0)

<h3>Learn more </h3>

statement about electrons and atomic orbitals

brainly.com/question/1832385

Effective nuclear charge

brainly.com/question/5441986

statement about subatomic particles is true

brainly.com/question/3176193

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At 25◦C and atmospheric pressure the volume change of mixing of binary liquid mixtures of species 1 and 2 is given by)2545(2121x
lions [1.4K]

The question is incomplete. The complete question is:

At 25◦C and atmospheric pressure the volume change of mixing of binary liquid mixtures of species 1 and 2 is given by the equation:

ΔV = x1x2(45x1 + 25x2)

Where ΔV is  in cm3-mol-1. At these conditions, the molar volumes of pure liquid 1 and 2 are V1= 110 and V2= 90 cm3-mol-1. Determine the partial molar volumes 1VE and 2VE in a mixture containing 40 mole percent of specie 1.

Answer:

1VE = 117.92 cm³.mol⁻¹, 2VE = 97.92 cm³.mol⁻¹

Explanation:

In the equation given, x represents the molar fraction of each substance, thus x1 = 0.4 and x2 = 0.6. Because of the mixture, the molar partial volume of each substance will change by a same amount, which will be:

ΔV = 0.4*0.6(45*0.4+ 25*0.6)

ΔV = 7.92 cm³.mol⁻¹

1VE - V1 = 7.92

1VE = 7.92 + 110

1VE = 117.92 cm³.mol⁻¹

2VE - V2 = 7.92

2VE = 7.92 + 90

2VE = 97.92 cm³.mol⁻¹

3 0
3 years ago
Empirical formula of 25.13g sulfur and 49.87g copper
antiseptic1488 [7]

Copper + sulfur create copper sulfide.

It's a lengthy process to find the empirical formula:

Sulfur:

25.13g * \frac{1 mol}{32.065 g} = 0.78 mol

Copper:

49.87 * \frac{1 mol}{63.546 g} = 0.78mol

S:Cu => \frac{0.78}{0.78} :\frac{0.78}{0.78} => (1:1) * 1 => 1:1

The empirical formula would just be CuS

7 0
3 years ago
A scientist wants to use a model to help present the results of his detailed scientific investigation.
masha68 [24]

Answer:

Because the model makes the concepts easier to understand

Explanation:

Models are created to give a visual of every aspect of an experiment. This allows for a better understanding across the board for everyone.

8 0
3 years ago
3) a) (2 points) Label the 1H NMR spectrum of adipic acid by identifying key resonances. Use letters (a, b, c, etc.) to match Hs
Bess [88]

Answer:

The label of spectrum is attached.

Explanation:

adipic acid is equal to:

COOH - CH2 - CH2 - CH2 - CH2 - COOH

(1)            (2)      (3)       (3)       (2)       (1)

The structure of adipic acid indicates that it has 3 equivalent carbons, therefore it should have 3 peaks in the spectrum:

The first peak at approximately 172 ppm is from carbon (1) COOH. The second peak is at approximately 23 ppm and is by carbon number (3) CH2. and the third peak is at approximately 37 ppm and is due to group number (2) CH2.

3 0
3 years ago
If the molar mass of x (hco3) is 162 g/mol, determine the relative atomic mass of x.
Anastasy [175]

The relative atomic mass of x is 101 u.

Molar mass is calculated by adding the atomic mass of all the elements in a compound.

Molar mass of x(HCO₃) =162 g/mol

Atomic mass of H = 1 g/mol

Atomic mass of C =12 g/mol

Atomic mass of O = 16 g/mol

Therefore, molar mass of x(HCO₃) will be

= x + 1 + 12 + 3 x 16

We know that:

x + 1 + 12 + 3 x 16=162

x + 61 = 162

x = 101 g/mol

The relative atomic mass of x will be 101 u.

Learn more about molar mass here:

brainly.com/question/12127540

#SPJ4

7 0
2 years ago
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