Answer:
-4096
Step-by-step explanation:
8,-16,32,-64,128,-256,512,-1024,2048.-4096
It would be the top right
because they are increasing by intervals of 4 each time. it can’t be the others because top left those are increasing by 5, bottom left decreasing by 4, and bottom right decreasing by .5.
Answer: i) f(-9)= 66
ii)
.
iii) 
Step-by-step explanation:
The given function :
.
i) For f(-9) , the independent variable is x= -9.
Put x= -9 in given function , we get


Thus , f(-9)= 66
ii) For f(x+1) , the independent variable is x= x+1.
Replace x by x+1 in given function , we get
.
![[\because\ (a+b)^2=(a^2+b^2+2ab)]](https://tex.z-dn.net/?f=%5B%5Cbecause%5C%20%28a%2Bb%29%5E2%3D%28a%5E2%2Bb%5E2%2B2ab%29%5D)


Thus ,
.
iii)For f(-x) , the independent variable is x=-x.
Replace x by -x in given function , we get
.
[∵ (+)(-)=(-)]
Thus , 
Answers:
1) Given
2) angle 2 ** see note below
3) angle 3 ** see note below
4) converse of alternate exterior angle theorem
note: you can swap the answers for 2 and 3 and it doesn't matter
========================================================
Explanations:
1) This is given so we just simply state "given". It seems silly to repeat what is given, but this is how you start any geometry proof.
2 & 3) The answers here are angle 2 and angle 3 because they are both interior angles (on the inside of the parallel lines m and L) and they are on alternate sides of the transversal line q. So they are both alternate interior angles and are congruent due to line L parallel to line m (alternate interior angle theorem)
4) If you have a pair of parallel lines, then the alternate exterior angle theorem says that alternate exterior angles are congruent. Going in reverse, the converse of this theorem says that having a pair of congruent alternate exterior angles (angle 1, angle 2) leads to the lines being parallel (p and q).
Answer:
Therefore, the four intervals are
(1) 6 - 6.59
(2) 7 - 7.59
(3) 8 - 8.59
(4) 9 - 9.59
The four frequencies are
(1) 4
(2) 3
(3) 1
(4) 6
Step-by-step explanation:
From the data, we have
Interval Frequency
1st 6 - 6.59 4
2nd 7 - 7.59 3
3rd 8 - 8.59 1
4th 9 - 9.59 6
Therefore, the four intervals are
(1) 6 - 6.59
(2) 7 - 7.59
(3) 8 - 8.59
(4) 9 - 9.59
The four frequencies are
(1) 4
(2) 3
(3) 1
(4) 6