Answer:




Step-by-step explanation:
Given:

Solving (a): P(x < 810)
To solve this, we make use of:

Because

So:



Hence:

Solving (b): P(x < 800)
To solve this, we make use of:

Because:

So:

Solving (c): P(x > 808.40)
Here, we make use of complement rule:

Where:



So:


Solving (d) The probability that the temperature lies outside 805.60 and 808.40
First, we calculate the probability that it lies within.
This is represented as:

This is calculated using:





Using complement rule, the required probability is:

