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igor_vitrenko [27]

2 years ago

8

Please help I’ll mark you as brainliest if correct

1 answer:

Snowcat [4.5K]2 years ago

3 0

Answer:

The answer to this is C. The dinosaur is about 5 feet taller than the person.

Step-by-step explanation:

The reason why is because the human is 4 feet since it says that 1/2 inch on the scale is 2 feet and the human is 1 inch on the scale so the human is 4 feet.

The dino is 8 feet since it goes to 2 inches on the scale which means 8 feet. The difference between 4 and 8 is 4, so 5 feet is the approximate for this problem.

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Which equation represents a proportional relationship?

asambeis [7]

Given:

Four equations in the options.

To find:

The equation which represents a proportional relationship.

Solution:

If y is proportional to x, then

$y\propto x$

$y=kx$

where, k is the constant of proportionality.

In this case if x=0, then y=0. It means the graph of a proportional relationship passes through the origin.

From the given options, only option B, i.e., $y=\dfrac{1}{4}x$ , is of the $y=kx$ , where, $k=\dfrac{1}{4}$ .

So, the equation $y=\dfrac{1}{4}x$ represents a proportional relationship.

Therefore, the correct option is B.

6 0

2 years ago

pantera1 [17]

Answer:

no solution

Step-by-step explanation:

p-4=-9+p

p=-5+p

0=-5

8 0

3 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

2 years ago

Plz help asap really need it

luda_lava [24]

Answer:

9

Step-by-step explanation:

perfect square sholud be $(a+b)^{2}$

so (w+3)*(w+3) is perfect square and extention of it is =>w*w+6w+9

6 0

2 years ago

Write the expanded form or fraction 24.357

creativ13 [48]

Fraction- 24 357
-------
1000

4 0

3 years ago

Read 2 more answers