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2 years ago

Solve the equations help

Mathematics

1 answer:

Leni [432]2 years ago

5 0

Answer:

First equation x=2, Y=9, Second Eq, x=2, y=1

Step-by-step explanation:

X+Y=11

2X-Y=-5 by substitution Y=11-X

So, 2x-(11-x)=-5, 2x-11+x=-5, 3x=6, x=2. Thus, Y=11-2=9

2x+y=5

3x-2y=4

so, y=5-2x

Thus, 3x-2(5-2x)=4

3x-10+4x=4, 7x=14, x=2, Thus, Y=5-2(2)= 1

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3 years ago

Write the following: a) 16 as a fraction of 152 b) 15 as a fraction of 210

Nesterboy [21]

Answer:

$\frac{16}{152}$

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Step-by-step explanation:

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2 years ago

Read 2 more answers

What is -2 sqrt 50 - sqrt 125 in simplest radical form

Gnoma [55]

Answer:

- 10√2 - 5√5

Step-by-step explanation:

- 2√50

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- 2√50

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= - 10√2

- √125

= - √( 5 x 5 x 5 )

= - 5√5

- 2√50 - √125

= - 10√2 - 5√5

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2 years ago

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How many ways can 6 people be seated in 4 seats

mojhsa [17]

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3 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

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